Answer:
He could have 4 dimes, or 8 nickles, or 1 quater and 3 nickels, or 1 quater with one dime and 1 nickel, or 3 dimes and 2 nickles, or 1 quater with obe nickel and one dime.
Step-by-step explanation:
hope this helps.
Answer:
Any value of x x makes the equation true. All real numbers Interval Notation: ( − ∞ , ∞ )
.
When putting data into a class for this case, 0.350 - 0.359, they should be within the class boundaries. The class boundaries are 0.3495 and 0.3595. So, the data that will go into that class are 0.356 and 0.358. The record 0.349 is not included since it is below 0.3495. Therefore, there are only two values in the class.
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Answer:
(A)(12, 9)
Step-by-step explanation:
Given:
The beginning of the left edge of the stencil falls at (2, −1).
A point, say Q on the stencil is at (4, 1).
Point Q divides the stencil into the ratio 1:4.
We are required to find the end of the stencil.
Mathematically, Point Q divides the stencil internally in the ratio 1:4.
For internal division of a line with beginning point 
and end point 
in the ratio m:n, we use the formula
, 
, Q(x,y)=(4,1), m:n=1:4
Therefore:
The correct option is A.
To determine the cost of each item, we need to set up equations. From the problem statement, we have three unknowns so we need three equations. We set up equations as follows:
let x cost of small pizzas
y cost of soda
z cost of salad
two small pizzas, a liter of soda, and a salad cost $14
2x + y + z = 14
one small pizza, a liter of soda, and three salads cost $15
x + y + 3z = 15
three small pizzas, a liter of soda, and two salads cost $22
3x + y + 2z = 22
Solving for x, y and z, we will have:
x = $ 5
y = $ 1
z = $ 3
