The function of the trapezoid area is:
A(x)=(B+b)*h/2
Where B and b are the bases and h is the height.
With the given data: h=10 B and b =7 and x (it may vary which one is bigger)
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So that function becomes:
A(x)=(7+x)*10/2
A(x)=(7+x)*5
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So if you want the inverse function, you have to operate to find x:
A(x)/5=7+x
A(x)/5-7=x
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So the new function is:
x(A)=A/5-7
We have to find how the chess player can move a knight from one location to another.
Also we have to remember that the bottom - left square is labelled ( 1 , 1 ).
First he wants to move a knight from ( 3 , 2 ) to ( 5 , 1 ).
Answer: 2 squares left, 1 square down.
Then he wants to move it from ( 5 , 1 ) to ( 6 , 3 ).
Answer: 2 squares right, 2 squares up, 1 square left.
70 miles , 333.15km , average speed 112 kilometers/hours
Answer:
a) 10/3
b) hyperbola
c) x = ± 6/5
Step-by-step explanation:
a) A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:
Given the conic equation: 
We have to make it to be in the form :
Comparing with
e = 10/3 = 3.3333, p = 6/5
b) since the eccentricity = 3.33 > 1, it is a hyperbola
c) The equation of the directrix is x = ±p = ± 6/5
