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san4es73 [151]
2 years ago
13

The rule for the dilation of quadrilateral QRST to the image Q'R'S'T' is DO,0.5(x, y) → (0.5x, 0.5y). What are the coordinates o

f Q', if Q(0, 2)?
Mathematics
2 answers:
OLga [1]2 years ago
7 0
Applying the rule for dilation, we will multiply the scale factor to its coordinates. Having Q (0,2) and DO 0.5(x.y), the coordinates of Q' will be:
x = (.5)(0) = 0y = (.5)(2) = 1
Therefore coordinates of Q' is (0,1) 
*Having a scale factor of >1, the figure is said to be reduced.


defon2 years ago
5 0

Answer:

(0,1)

Step-by-step explanation:


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What’s the largest fraction in each group? a. 5⁄6 and 29⁄36 b. 5⁄12 and 3⁄8 c. 2⁄5 and 19⁄45 d. 5⁄7, 13⁄14, and 19⁄21 e. 7⁄11 an
Mariulka [41]
Imagine a cake. OK? Now divide the cake in 2 equal pieces, each one is ½ of the cake.
Now divide each piece in 2 halves; each one is ¼ of the cake. Witch is largest? 1:2=0,5; 1:4=0,25. 0,5>0,25.

5:6=0,83333
29:36=0,80555
0,83>0,80 so 5/6 is the largest.

Do this for each group.

a.5/6
b.5/8
c.19/45
d.13/14
e.7/11
f.1/2
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2 years ago
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While analyzing the landing procedures of airplanes, George noted one plane at an altitude of 5,000 feet descending at a rate of
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Answer:

C

Step-by-step explanation:


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Sophie did an anyonymous survey and collected her friends' credit scores. the scores she found are listed in the table below. wh
MrRissso [65]

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2 years ago
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3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a pa
Artist 52 [7]

Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 15000, p = 0.09

So

\mu = E(X) = np = 15000*0.09 = 1350

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1499 - 1350}{35.05}

Z = 4.25

Z = 4.25 has a pvalue of 1.

1 - 1 = 0

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6 0
2 years ago
The pie chart below shows the percentage of total revenue that a publisher receives from various types of publications. Use this
liberstina [14]

Answer:

a. Cookbooks

b. 50%

c. 30%

Step-by-step explanation:

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Thus, cookbooks are less than 90°.

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So, Answer For (a) is Cookbooks  

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So, the Total Revenue Comes From Textbooks & Cookbooks is 50%.

c. Now We know the Cookbooks + Textbooks Revenue form 180° Approximately & Cookbook is approximately equal to 72° (as we solve above)

So, textbooks are 180°-72° = 108°, which is 30% of 360° ∴ 30% Revenue Come From Textbooks.

7 0
2 years ago
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