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Vikentia [17]
2 years ago
6

A volunteer is organizing the snacks at a concession stand and notices the ratio is sweet snacks to salty snacks is 5:1. If ther

e are 20 salty snacks , how many sweet snacks are at the concession stand?
Mathematics
1 answer:
Verizon [17]2 years ago
3 0
100 sweet snack, if it is 5:1 ratio than there’s 5 times the amount of salty snacks
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A mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt. Th
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Answer:

The probability of hitting the bullseye at least once in 6 attempts is 0.469.

Step-by-step explanation:

It is given that a mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt.

The probability of hitting bullseye in each attempt, p = 0.10

The probability of not hitting bullseye in each attempt, q = 1-p = 1-0.10 = 0.90

Let x be the event of  hitting the bullseye.

We need to find the probability of hitting the bullseye at least once in 6 attempts.

P(x\geq 1)=1-P(x=0)       .... (1)

According to binomial expression

P(x=r)=^nC_rp^rq^{n-r}

where, n is total attempts, r is number of outcomes, p is probability of success and q is probability of failure.

The probability that the dart thrower not hits the bullseye in 6 attempts is

P(x=0)=^6C_0(0.10)^0(0.90)^{6-0}

P(x=0)=0.531441

Substitute the value of P(x=0) in (1).

P(x\geq 1)=1-0.531441

P(x\geq 1)=0.468559

P(x\geq 1)\approx 0.469

Therefore the probability of hitting the bullseye at least once in 6 attempts is 0.469.

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