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Alex787 [66]
2 years ago
15

Use the vertical line test to determine if the graph below represents a function. If it is not a function, tell where the vertic

al line test fails.

Mathematics
2 answers:
katen-ka-za [31]2 years ago
7 0

Answer:

1: Function    2: Function   3: Not a Function

Step-by-step explanation:

there-

Step2247 [10]2 years ago
3 0

Answer:

see attached

Step-by-step explanation:

The vertical line test for a function passes when, if you draw a vertical line which intersects the graph, the line intersects the graph at ONLY ONE point.

It is quite clear that for all positive values of X, any vertical line will intersect the graph at 2 points, thereby failing the vertical line test for a function.

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Consider the following formula used to estimate height, h, of a seedling after w weeks since planting:
svp [43]

Answer:

Option B. w=5h-8

Step-by-step explanation:

we have

h=(\frac{1}{5})w+(\frac{8}{5})

Solve for w

That means ----> isolate the variable w

Multiply by 5 both sides to remove the fraction

5h=w+8

subtract 8 both sides

5h-8=w+8-8

5h-8=w

Rewrite

w=5h-8

4 0
2 years ago
The sales data for January and February of a frozen yogurt shop are approximately normal. The mean daily sales for January was $
VashaNatasha [74]

Answer:

January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.

Step-by-step explanation:

z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

January:

The mean daily sales for January was $300 with a standard deviation of $20. On the 15th of January, the shop sold $310 of yogurt. This means, respectively, that \mu = 300, \sigma = 20, X = 310. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{310 - 300}{20}

Z = 0.5

February:

The mean daily sales for February was $320 with a standard deviation of $50. On the 15th of February, the shop sold $340 of yogurt. This means, respectively, that \mu = 320, \sigma = 50, X = 340. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{340 - 320}{50}

Z = 0.4

January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.

3 0
2 years ago
Jason collects baseball cards. He bought one card for $25. Its current value is represented by the expression 25(1.02)t, where t
ki77a [65]
Is Jason’s baseball card going up by 2% every year for example

Jason’s baseball card after 1 year is
25×(1.02)^(1)=25.5
It increased by 0.5 in amount after one year
4 0
2 years ago
22.Lenin is preparing dinner plates. He has 12 pieces of chicken and 16 rolls. If he wants to make all the plates identicalwitho
Nitella [24]

Answer: The greatest number of plates Lenin can prepare = 4

and there will be 3 chickens and 4 rolls in each plate.

Step-by-step explanation:

Given: Lenin is preparing dinner plates. He has 12 pieces of chicken and 16 rolls.

To make all the plates identical without any food left over, the greatest number of plates Lenin can prepare = G.C.D.(12,16)=4

The number of pieces of chicken in each plate = \dfrac{12}{4}=3

The number of pieces of rolls in each plate = \dfrac{16}{4}=4

So,  the greatest number of plates Lenin can prepare = 4

and there will be 3 chickens and 4 rolls in each plate.

7 0
2 years ago
Chloe made a conjecture that given any two numbers, the greater number can always be arranged into more arrays.
Anna11 [10]

Solution:

Array means arrangement of numbers in terms of rows and columns.

The conjecture is not True.

So, the conjecture made by chloe that given any two numbers, the greater number can always be arranged into more arrays is not true.

For example ,

1.(2,3)

2→(2×1),(1×2)

3→(3×1),(1×3)

This pair has same number of arrays because both of them are prime.

2. (3,4)

Here, 4>3

3→ (3 × 1),(1×3)

4→(4×1),(1×4),(2×2)

The pair of numbers are Co-prime, one of them is not prime. So Composite number has more number of arrays.

4. (6,11)

6→(1×6),(6×1),(2×3),(3×2)

11→(1×11),(11×1)

The number 6 is smaller, but it has more number of arrays.

5. (6,8)

6→(1×6),(6×1),(2×3),(3×2)

9→(1×9),(9×1),(3×3)

Both the numbers are composite.Smaller number 6 has more arrays.

These examples disprove the Conjecture made by Chloe, which states that given any two numbers, the greater number can always be arranged into more arrays.



4 0
2 years ago
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