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olganol [36]
2 years ago
13

If a is an arbitrary nonzero constant, what happens to a/b as b approaches 0

Mathematics
1 answer:
barxatty [35]2 years ago
5 0

Answer:

a/b tends to an infinite value

Step-by-step explanation:

If If a is an arbitrary nonzero constant, and we are to look for a/b as b approaches zero, we can represent this statement using limits. The statement is expressed as:

\lim_{b \to 0} \dfrac{a}{b}

Substituting b = 0 into the function

=  \dfrac{a}{0} \\\\= \infty \\\\\lim_{b \to 0} \dfrac{a}{b} = \infty\\ \\\\

<em></em>

<em>Since the limits of a tends to infinity as b tends to zero hence </em><em>we can conclude that If a is an arbitrary nonzero constant then a/b tends to infinity or is undefined as b approaches 0</em>

<em></em>

<em></em>

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the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev
Naya [18.7K]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 16}{2.1}

Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

Out of 180

0.0284*180 = 5.112 days

4 0
2 years ago
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