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velikii [3]
1 year ago
10

Ari is designing a patio that will be 20 feet long and 16 feet wide. He makes a scale drawing of the patio using a scale of 1 in

ch to 4 feet. The ratio of the area of the scaled drawing to the actual area of the patio is 1 square inch to ___ square feet.
Mathematics
2 answers:
lara31 [8.8K]1 year ago
6 0
Wouldnt it be four? id its 1/4

mixas84 [53]1 year ago
3 0

Answer:

1 square inch to 4 square feet.

Step-by-step explanation:

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PLZ HELP I WILL GIVE BRAINLIEST!!
VladimirAG [237]

Answer:

Part A

16 and 1/2 or 16 R6, 17 if you round up

Part B

Answer choices A and D are correct

6 0
2 years ago
Suppose we want to choose 2 objects, without replacement, from the 5 objects pencil, eraser, desk, chair, and lamp. (a)How many
BigorU [14]

Answer:

a) 20 ways

b) 10 ways

Step-by-step explanation:

When the order of selection/choice matters, we use Permutations to find the number of ways and if the order of selection/choice does not matter, we use Combinations to find the number of ways.

Part a)

We have to chose 2 objects from a group of 5 objects and order of choice matters. This is a problem of permutations, so we have to find 5P2

General formula of permutations of n objects taken r at time is:

nPr=\frac{n!}{(n-r)!}

Using the value of n=5 and r=2, we get:

5P2=\frac{5!}{(5-2)!} =20

Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice matters.

Part b)

Order of choice does not matter in this case, so we will use combinations to find the number of ways of choosing 2 objects from a group of 5 objects which is represented by 5C2.

The general formula of combinations of n objects taken r at a time is:

nCr=\frac{n!}{r!(n-r)!}

Using the value of n=5 and r=2, we get:

5C2=\frac{5!}{2!(5-2)!} =10

Therefore, we can choose 2 objects from a group of 5 given objects if the order of choice does not matters.

3 0
2 years ago
Read 2 more answers
An adult meerkat weighed 0.776 kilograms . this is 7.47 hectograms more than the weight of a baby meerkat . how much dose a baby
Firlakuza [10]
Let x = weight of adult meerkat, y=weight of baby meerkat, Find y.
x=0.776 kg
y+7.47hectogram=x=0.776
Since 1 hectogram = 0.1 kg,
Therefore the weight of baby meerkat is, y= 0.029 kg
7 0
2 years ago
Read 2 more answers
In △ABC,c=71, m∠B=123°, and a=65. Find b.<br><br> A. 101.5<br> B. 117.8<br> C. 123.0<br> D. 119.6
tia_tia [17]

Answer:

Option D

Step-by-step explanation:

The questions which involve calculating the angles and the sides of a triangle either require the sine rule or the cosine rule. In this question, the two sides that are given are adjacent to each other the given angle is the included angle. This means that the angle B is formed by the intersection of the lines a and c. Therefore, cosine rule will be used to calculate the length of b. The cosine rule is:

b^2 = a^2 + c^2 - 2*a*c*cos(B).

The question specifies that c=71, B=123°, and a=65. Plugging in the values:

b^2 = 65^2 + 71^2 - 2(65)(71)*cos(123°).

Simplifying gives:

b^2 = 14293.0182932.

Taking square root on the both sides gives b = 119.6 (rounded to the one decimal place).

This means that the Option D is the correct choice!!!

8 0
2 years ago
For 2, use the relationship between the values of the digits to solve Write a number in which the value of the 3 is ten times gr
larisa [96]

Answer:

New Digit = 315,864

Step-by-step explanation:

Given:

Digit - 135,864

Value of digit 3 = 30,000

Find:

New Digit, Value of 3 is 10 times greater

Computation:

Value of 3 is 10 times greater = (30,000) = 300,000

New Digit = 315,864

8 0
1 year ago
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