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alexira [117]
2 years ago
10

WHEN GIVEN A RAW SCORE, EXPLAIN HOW TO USE THE NORMAL CURVE TO COMPARE THAT SCORE TO THE POPULATION. WHAT IS A Z-SCORE?

Mathematics
1 answer:
valina [46]2 years ago
5 0

<span>1. </span>When given a raw score, it must be converted into a z-score (standard score). Raw scores cannot be placed on a normal distribution curve because they do not have the same means and standard deviations, but when it is converted into a z-score, the number of standard deviations above or below the population mean can be measured. The z-scores on the center are average, the scores on the left are lower than average and the scores on the right are higher than average.

<span>2. </span>A z-score is a standard score which can be placed on a normal distribution curve. A z-score indicates the distance of the standard deviations from the mean (center of the curve).

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Which graph represents a function?
Agata [3.3K]
The fourth one because to know if it is a function or not it has to pass the vertical line test the first one when you draw a vertical line some of the lines repeats so does the second and third but the last one when you draw a vertical line it doesn't repeat s that means its a function

8 0
2 years ago
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Pedro has created the function f(x)= 4x-3/2 to represent the number of assingments he has completed where x represents the numbe
Law Incorporation [45]
The given function is
f(x) = 4x - 3/2
where
f(x) = number of assignments completed
x =  number of weeks required to complete the assignments

We want to find f⁻¹ (30) as an estimate of the number of weeks required to complete 30 assignments.
The procedure is as follows:

1. Set y = f(x)
   y = 4x - 3/2

2. Exchange x and y
   x = 4y - 3/2

3. Solve for y
   4y = x + 3/2
   y = (x +3/2)/4

4. Set y equal to f⁻¹ (x)
  f⁻¹ (x) = (x + 3/2)/4

5. Find f⁻¹ (30)
  f⁻¹ (30) = (30 + 3/2)/4 = 63/8 = 8 (approxmately)

Answer:
Pedro needs about 8 weeks to complete 30 assignments.

6 0
2 years ago
A car was purchased for $25,000. Research shows that the car has an average yearly depreciation rate of 18.5%. Create a function
vitfil [10]

Answer:

V(t) = 25000 * (0.815)^t

The depreciation from year 3 to year 4 was $2503.71

Step-by-step explanation:

We can model V(t) as an exponencial function:

V(t) = Vo * (1+r)^t

Where Vo is the inicial value of the car, r is the depreciation rate and t is the amount of years.

We have that Vo = 25000, r = -18.5% = -0.185, so:

V(t) = 25000 * (1-0.185)^t

V(t) = 25000 * (0.815)^t

In year 3, we have:

V(3) = 25000 * (0.815)^3 = 13533.58

In year 4, we have:

V(4) = 25000 * (0.815)^4 = 11029.87

The depreciation from year 3 to year 4 was:

V(3) - V(4) = 13533.58 - 11029.87 = $2503.71

7 0
2 years ago
What's the angle of x?
vichka [17]

Answer:

60 as corresponding and alternate angles r equal

Step-by-step explanation:

3 0
1 year ago
Read 2 more answers
Cheese costs $4.40 per pound. Find the cost per kilogram. (1kg = 2.2lb)
MakcuM [25]

Answer:

The cost is $9.70 per kilogram.

Step-by-step explanation:

This can be solved by a rule of three.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.

In this problem, the measures are the weight of the cheese and the price. As the weight increases, so does the price. It means that this is a direct rule of three.

Solution:

The problem states that cheese costs $4.40 per pound. Each kg has 2.2 pounds. How many kg are there in 1 pound. So:

1 pound - xkg

2.2 pound - 1 kg

2.2x = 1

x = \frac{1}{2.2}

x = 0.45kg

Since cheese costs $4.40 per pound, and each pound has 0.45kg, cheese costs $4.40 per 0.45kg. How much does is cost for 1kg?

$4.40 - 0.45kg

$x - 1kg

0.45x = 4.40

x = \frac{4.40}{0.45}

x = 9.70

The cost is $9.70 per kilogram.

6 0
2 years ago
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