For this case we have that the variable "x" represents the number of hours that Leticia uses to take care of children on Saturday.
IF on Friday I use 4 hours ($ 8 each) and on Saturday "x" hours ($ 8 each) obtaining a profit of $ 72, we have the following equation:
We apply distributive property:
So, on Saturday she spent 5 hours.
Answer:
Answer:
124.67cm³
Step-by-step explanation:
==>Given:
Dimensions of current can:
Height (h) = 12cm
Diameter = 6cm (radius = 3cm)
Volume of current can (V1) = 339.12 cm³
Dimensions of future cans to be increased multiple of 1.11:
height = 12cm × 1.11 = 13.32 cm
radius = 3cm × 1.11 = 3.33 cm
Volume of future can (V2) = πr²h = 3.14*3.33²*13.32
= 3.14*11.0889*13.32 = 463.791025
V2 ≈ 463.79 cm³
==>Find how much more would new cans hold = Volume of new can - volume of current can
= 463.79 cm³ - 339.12 cm³
= 124.67cm³
Solution:
Matte Satin Glossy Total
Homeowners 0.08 0.20 0.24 0.52
Contractors 0.04 0.26 0.18 0.48
Total 0.12 0.46 0.42 1
Approximately what percentage of contractors prefer the glossy finish?
Answer: Percentage of contractors who prefer the glossy finish is:
or 
Therefore, the option D. 37.5% is correct
Answer:
The answer is explained below
Step-by-step explanation:
STEP 1
Out of 1500 units produced by a company 1,477 are found to be free of a particular type of defect. One needs to rate the performance based on Six Sigma Theory.
STEP 2
Manager can define the performance of a product using defects per million units DPMO metric
DPMO can be find by using
DPMO = Total number of defects in a sample/ No. of opportunities of per error per unit x No. of units * 1,000,000
= 1500 - 1477/ 1 x 1500* 1,000,000
= 23/1500
= 15,333,33
The defect rate of the process can be find by
Defect rate = No. of defects/ No. of units * 100
= 1500 - 1477/1500 * 100
= 23/1500 * 100
= 1.53%
Six Sigma theory focuses on achieving 3.4 defects per million for a certain period of time. However in this, performance of the process is not as good as stated by the manager.
