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Reptile [31]
2 years ago
11

As part of Kayla's exercise program,she either runs 6miles/day or rides her bike 10 miles/day.Her new goal is to cover a minimum

distance of 200 miles,with at least 15 of the days running.She would like to determine the number of days it would take to accomplish this.

Mathematics
1 answer:
poizon [28]2 years ago
8 0
6(15) + 10b > = 200
90 + 10b > = 200
10b > = 200 - 90
10b > = 110
b > = 110/10
b > = 11

so she can do 15 days of running plus 11 days of biking....which totals 26 days

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Fran graphs the equations y = 2x2 – 2 and y = –0.5x + 4. Her graph is shown below. mc010-1.jpg Which value is an approximate sol
miv72 [106K]
On the added picture you can see that graphs of functions y=2x^2-2 and y=-0.5x+4 have two points of intersection. The x-coordinates of these points are the solutions of the equation 
2x^2-2=-0.5x+4.
Hence, the approximate solutions are x=-1.9 and x=1.6.


3 0
2 years ago
Read 2 more answers
Find the solution set of the following equations: <br><br>2y=2x+7<br><br>X=y+2
kirill115 [55]

Answer:

The system of equations has no solution.

Step-by-step explanation:

Given the system of equations

2y = 2x+7

x = y+2

solving the system of equations

\begin{bmatrix}2y=2x+7\\ x=y+2\end{bmatrix}

Arrange equation variables for elimination

\begin{bmatrix}2y-2x=7\\ -y+x=2\end{bmatrix}

Multiply -y+x=2 by 2:  -2y+2x=4

\begin{bmatrix}2y-2x=7\\ -2y+2x=4\end{bmatrix}

so adding

-2y+2x=4

+

\underline{2y-2x=7}

0=11

so the system of equations becomes

\begin{bmatrix}2y-2x=7\\ 0=11\end{bmatrix}

0 = 11 is false, therefore the system of equations has no solution.

Thus,

No Solution!

3 0
2 years ago
Let f be the function given by f(x)=3xsinx. What is the average value of f on the closed interval 1≤x≤7 ?
Hoochie [10]

Answer:

-2.92178

Step-by-step explanation:

Given the function f(x)=3x\ sin x

The average,A is calculated using the formula;

A=\frac{1}{b-a}\int\limits^a_b F(x)\, dx \\\\A=\frac{1}{7-1}\int\limits^7_1 3x \ Sin \ x\, dx \\\\\\=\frac{3}{6}\int\limits^7_1 x \ Sin \ x\, dx \\\\\#Integration\  by\  parts, u=x, v \prime=sin(x)\\=0.5[-xcos(x)-\int-cos(x)dx]\limits^7_1\\\\=0.5[-xcos(x)-(-sin(x))]\limits^7_1\\\\=0.5[-xcos(x)+sin(x)]\limits^7_1\\\\=0.5[-6.82595--0.98240]\\\\=-2.92178

Hence, the average of the function is -2.92178

8 0
2 years ago
A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance tra
alina1380 [7]

Answer:

1.734

Step-by-step explanation:

Given that:

A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles).

The fitted regression is Time = −7.126 + .0214 Distance

Based on a sample size n = 20

And an Estimated standard error of the slope = 0.0053

the critical value for a right-tailed test to see if the slope is positive, using ∝ = 0.05 can be computed as follows:

Let's determine the degree of freedom df = n - 1

the degree of freedom df = 20 - 2

the degree of freedom df =  18

At the level of significance ∝ = 0.05 and degree of freedom df =  18

For a right tailed test t, the critical value from the t table is :

t_{0.05, 18} = 1.734

5 0
2 years ago
HELP!!!!!!<br><br> y = 6kx - 2; m = 2/3
Mrrafil [7]

Answer:

k=1/9

Step-by-step explanation:

6k is the slope , and you actual slope(m) is given, hence,make em equal to each other:

6k = 2/3

k = 2/3(6) [Divide both sides by 6]

k = 1 /9 [Simplify]

Hope this helps!

Mark brainliest if you think I helped!

Would really appreciate!

7 0
2 years ago
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