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Rus_ich [418]
2 years ago
13

A dust particle weighs 7.42 × 10-10 kilograms. What is the weight of 5 × 106 dust particles represented in scientific notation?

Mathematics
2 answers:
vova2212 [387]2 years ago
7 0

5 x 106 = 530 particles

530 x 7.42x10^-10 = 3.93x10^-7

elena55 [62]2 years ago
5 0

B.  

3.71 × 10-3 kilograms

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Faelyn grouped the terms and factored the GCF out of the groups of the polynomial 6x4 – 8x2 + 3x2 + 4. Her work is shown.
Y_Kistochka [10]
It is hard to say how Faelyn's work shows the polynomial is prime, but it is.

There are no factors of 6*4 = 24 that add to -5, so the polynomial cannot be factored using real numbers.
_____
The expression of suggestion 2 is a different polynomial than the one Faelyn is factoring.
Taking a factor of 2x out of the first group does not help it match the factoring of the second group.
Dividing one or the other of the groups by -1 will not make the binomials the same.
8 0
2 years ago
Read 2 more answers
2.14x - 42.9 for x = 22.4 ?<br> A. -18.36<br> B. 5.026<br> C. 47.939<br> D. 90.839
Fynjy0 [20]

Answer:

Step-by-step explanation:

Your answer would be B., because you would multiply

2.14 x  22.4   =

47.939  

then you will subtract that by 42.9

47.939 - 42.9 =  

5.026

7 0
2 years ago
PLS HELP ASAP I WILL IVE BRAINLIST ANSWER!!!!!Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using thi
Juliette [100K]

Answer:

Leon is correct. (Option 1)

Step-by-step explanation:

Given that Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using this procedure.

Step 1: Find the greatest common factor of the given lengths: 7

Step 2: Divide the given lengths by the greatest common factor: 3, 4, 5

Step 3: Verify that the lengths found in step 2 form a Pythagorean triple.

we have to explain whether or not Leon is correct.

As, 3,4,5 forms a Pythagorean triplet i.e satisfies the Pythagoras theorem

Hypotenuse^2=Base^2+Perpendicular^2

⇒ 5^2=3^2+4^2

Let a, b, c forms a Pythagorean triplet

a^2+b^2=c^2

Multiplied by 4 on both sides

⇒ 4a^2+4b^2=4c^2

⇒ {2a}^2+{2b}^2={2c}^2

Hence, we say 4a, 4b and 4c also forms a Pythagorean triplet.

∴ multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.

Hence, Leon is correct.

4 0
2 years ago
Read 2 more answers
How to factorise 5h^2-12hg​
bonufazy [111]

Answer:

h(5h-12g)

Step-by-step explanation:

5h^2-12hg

When we factor expressions, we look for factors within the terms that are alike, or in other words, we look for common factors. Here, 5h^2 and 12hg only have one common factor: h. Therefore, to factorize this expression, divide both terms by h.

= h(\frac{5h^2}{h}-\frac{12hg}{h}  )\\= h(5h-12g)

Now, we've "carried" h out of the expression and have therefore factored it.

I hope this helps!

7 0
2 years ago
Simplify 14.2 + 6.5(p + 3q) – 4.05q
anzhelika [568]
Answer is C
14.2+6.5(p+3q)-4.05q
14.2+6.5p+19.5q-4.05q
14.2+6.5p+15.45q→6.5p+15.45q+14.2
so the answer is C
7 0
2 years ago
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