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Verizon [17]
2 years ago
5

Alex is making 12 pennants for the school fair.The pattern he is using to make the pennants is shown in the figure.The fabricfor

the pennants costs $1.25 per square foot. How much will it cost Alex to make 12 pennants?
—
THIS IS URGENT!!!!
PLEASE ANSWER WITH WORK.
Mathematics
2 answers:
Rzqust [24]2 years ago
8 0
It will cost Alex 15$
ipn [44]2 years ago
6 0
So hes making 12 pennants and they cost $1.25 each so you would just mutiply them by each otber which equals $15.00
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The soccer team collected $800 at a car wash fundraiser. They charged $5.00 for small vehicles and $10.00 for larger vehicles. T
Katyanochek1 [597]

5x + 10y = 800

y = 50

10y = 10*50 = 500

800 - 500 = 300

300/5 = 60

x = 60

5(60) + 10(50) = 800

60 small vehicles were washed in total

8 0
2 years ago
Read 2 more answers
At higher altitudes, water boils at lower temperatures. This relationship between altitude and boiling point is linear. At an al
Mashutka [201]

Let's assume

boiling point is y

altitude is x

we are given

This relationship between altitude and boiling point is linear

At an altitude of 1000 feet, water boils at 210°F

so, first point is (1000,210)

so, x1=1000 , y1=210

At an altitude of 3000 feet, water boils at 206°F

so, second point is (3000,206)

so, x2=3000,y2=206

now, we can find slope

m=\frac{y_2-y_1}{x_2-x_1}

now, we can plug values

m=\frac{206-210}{3000-1000}

m=-\frac{1}{500}

now, we can use point slope form of line

y-y_1=m(x-x_1)

so, we can plug it

y-210=-\frac{1}{500}(x-1000)

so, point slope form of line is

y-210=-\frac{1}{500}(x-1000)

now, we can plug x=8000

and then we can solve for y

y-210=-\frac{1}{500}(8000-1000)

y=196

So,

the boiling point of water at an altitude of 8000 feet is 196°F..........Answer

4 0
2 years ago
Read 2 more answers
Neptune’s average distance from the sun is 4.503 x 10e9 km. Mercury’s average distance from the sun is 5.791 x10e9 km.about how
Igoryamba

Answer:

77.76 times

Step-by-step explanation:

The average distance of Neptune  from the sun

= 4.503  ×  10 ⁹  k m .

and Mercury  =  5.791  ×  10 ⁷ k m .

Hence neptune is (  4.503  ×  10 ⁹) ÷ (5.791 × 10 ⁷  ) times farther from the sun than mercury

i.e.(  \frac{4.503}{5.791} )  × 10⁹⁻⁷ times

=   0.7776  ×  10 ² times

=   77.76  times.

4 0
2 years ago
As part of a class project, a university student surveyed the students in the cafeteria lunch line to look for a relationship be
Vedmedyk [2.9K]

Answer:

0.63

Step-by-step explanation:

To get the relative frequency of students with red hair, we need to find the relative frequency of students with red hair from the students with gray eyes.

Since we already know that the total number of students with gray eyes is 35 and the number of red hair students with gray eye is 22

The formula we will use to calculate the relative frequency will be

The relative frequency of students with red hair = Total students of red hair with gray eyes divide by total number of gray eye students

22 ÷ 35 = 0.628  ≅ 0.63

6 1
2 years ago
The value of the coefficient of correlation ( r) a. can never be equal to the value of the coefficient of determination (r2). b.
gulaghasi [49]

Answer:

d. can be equal to the value of the coefficient of determination (r2).

True on the special case when r =1 we have that r^2 = 1

Step-by-step explanation:

We need to remember that the correlation coefficient is a measure to analyze the goodness of fit for a model and is given by:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

The determination coefficient is given by R= r^2

Let's analyze one by one the possible options:

a. can never be equal to the value of the coefficient of determination (r2).

False if r = 1 then r^2 = 1

b. is always larger than the value of the coefficient of determination (r2).

False not always if r= 1 we have that r^2 =1 and we don't satisfy the condition

c. is always smaller than the value of the coefficient of determination (r2).

False again if r =1 then we have r^2 = 1 and we don't satisfy the condition

d. can be equal to the value of the coefficient of determination (r2).

True on the special case when r =1 we have that r^2 = 1

7 0
2 years ago
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