What is 119,000,003 in expanded form

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation: 22, 18, 1

BigorU [14]

Answer:

a: Sample mean: 20, Sample standard deviation: 1.732

b: 19.13 <µ < 20.87

c: 18.84< µ < 21.16

d: as the confidence level increases, the interval becomes wider

Step-by-step explanation:

a: Sample mean is found by adding up all the individual values of the sample, then dividing by the total number of values in the sample.

Sample standard deviation is the square root of the variance

See the first attached photo for the calculations of these values.

We need to create a 80% confidence interval for the population. Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.

Look for the column on the t-distribution chart that has "area in two tails" of 0.20 (80%), and row 7 (degree of freedom)

The t-value is 1.415

See the second attached photo for the construction of the confidence interval

We need to create a 90% confidence interval for the population. Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.

Look for the column on the t-distribution chart that has "area in two tails" of 0.10 (90%), and row 7 (degree of freedom)

The t-value is 1.895

See the third attached photo for the construction of the confidence interval

3 0

2 years ago

A man on a diet is losing four-tenths of a kilogram each day. How many days will it take him to lose 3.2 kilograms?

Alborosie

so he's losing 4/10 of a Kg daily, how many times will that equal 3.2 Kgs? namely how many times does 4/10 go into 3.2?

well, let's firstly convert 3.2 to a fraction, and then divide.

$\bf \stackrel{\textit{1 decimal}}{3.\underline{2}}\implies \cfrac{32}{\underset{\textit{1 zero}}{1\underline{0}}}\implies \cfrac{16}{5} \\\\[-0.35em] ~\dotfill$

$\bf \cfrac{16}{5}\div \cfrac{4}{10}\implies \cfrac{16}{5}\div \cfrac{2}{5}\implies \cfrac{\stackrel{8}{~~\begin{matrix} 16 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\cdot \cfrac{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies 8$

3 0

1 year ago

After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos

igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

$d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}$

and we found the distance PQ and QA

; $d_{PQ}=\sqrt{125}$ , $d_{QA}=12$

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0

1 year ago

The buyer for an electronics store wants to estimate the proportion of defective wireless game controllers in a shipment of 5,00

katrin2010 [14]

Answer:

We conlude that it is cluster random sample.

Step-by-step explanation:

We know that:

The buyer for an electronics store wants to estimate the proportion of defective wireless game controllers in a shipment of 5,000 controllers from the store's primary supplier. The shipment consists of 200 boxes each containing 25 controllers. The buyer numbers the boxes from 1 to 200 and randomly selects six numbers in that range. She then opens the six boxes with the corresponding numbers, examines all 25 controllers in each of these boxes, and determines the proportion of the 150 controllers that are defective.

We conlude that it is cluster random sample.

4 0

2 years ago

Megan went clothes shopping and bought 2 pairs of flare jeans, 2 camisoles, and 4 t-shirts for $90.00. at the same store, paige

liq [111]

If you let j, c, t represent the prices of jeans, camisoles, and t-shirts, respectively, the three purchases can be described by ...
2j +2c +4t = 90.00
1j +0c +3t = 42.50
1j +3c +2t = 62.00

It is convenient to let a calculator solve these equations. It can tell you the row-reduced matrix equations are ...
[[1 0 0 24.5]
[0 1 0 8.5 ]
[0 0 1 6 ]]
which means
flare jeans cost $24.50
camisoles cost $8.50
T-shirts cost $6.00

6 0

2 years ago