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2 years ago

7

A computer downloaded 20 kilobytes of data in 4 seconds. If it downloads data at a constant speed, it can download ______ kiloby

tes of data in 15 seconds

2 answers:

True [87]2 years ago

4 0

Answer:

75 kb

Step-by-step explanation:

Kaylis [27]2 years ago

3 0

Answer:75

Step-by-step explanation:

Divide 20 by 4 to get 5, the number of kb per second, and multiply by 15 to get 75

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A baker uses 13 1/2 cups of flour to make bread. She uses 2 1/4 cups of flour to make each loaf. The baker sells 2/3 of the loav

ollegr [7]

Answer:

She sells 4 loaves of bread

Step-by-step explanation:

Lets explain how to solve the problem

→ A baker uses $13\frac{1}{2}$ cups of flour to make bread

→ She uses $2\frac{1}{4}$ cups of flour to make each loaf

From these information we can find the number of loaves of bread

she can make

∵ There are $13\frac{1}{2}$ cups of flour

∵ Each loaf of bread needs $2\frac{1}{4}$ cups of flour

∴ The number of loaves = $13\frac{1}{2}$ ÷ $2\frac{1}{4}$

To divide two mixed numbers make them improper fractions and

change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∵ $13\frac{1}{2}$ = $\frac{(13)(2)+1}{2}$

∴ $13\frac{1}{2}$ = $\frac{27}{2}$

∵ $2\frac{1}{4}$ = $\frac{(2)(4)+1}{4}$

∴ $2\frac{1}{4}$ = $\frac{9}{4}$

∴ The number of loaves = $\frac{27}{2}$ × $\frac{4}{9}$

∴ The number of loaves = 6

<em>She can make 6 loaves</em>

→ The baker sells $\frac{2}{3}$ of the loaves of bread that she makes

→ We need to find the number of loves of bread she sells

∵ She sells $\frac{2}{3}$ of the loaves

∵ There are 6 loves

∴ The number of loaves she sells = 6 × $\frac{2}{3}$ = 4

<em>She sells 4 loaves of bread</em>

7 0

2 years ago

Compare write <>= 18,000g 10kg

ziro4ka [17]

10kg's is greater than 18,000 18,000 < 10kg

5 0

2 years ago

What is the distance, to the nearest whole number, from K (5, 6) to P (1, 1)?

Elza [17]

Answer:

<h3>The answer is 6 units</h3>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

K (5, 6) P (1, 1)

The distance from K to P is

$|KP| = \sqrt{ ({5 - 1})^{2} + ({6 - 1})^{2} } \\ = \sqrt{ {4}^{2} + {5}^{2} } \\ = \sqrt{16 + 25} \\ = \sqrt{41} \\ = 6.403124$

We have the final answer as

<h3>6 units to the nearest whole number</h3>

Hope this helps you

5 0

2 years ago

The perimeter of a triangle is 30 inches. After a dilation, the perimeter is 6 inches. What is the scale factor of the perimeter

Black_prince [1.1K]

1/5 is the answer brainiest plzzz i hope it helps

5 0

2 years ago

HELP ASAP In two or more complete sentences, Explain how you would find the equation of a parabola, given the coordinate of the

kvasek [131]

In the general case in Cartesian coordinates, you would use the definition of a parabola as the locus of points equidistant from the focus and directrix. The equation would equate the square of the distance from a general point (x, y) to the focus with the square of the distance from that point to the directrix line.

Suppose the focus is located at (h, k) and the equation of the directrix is ax+by+c=0. The expression for the square of the distance from (x, y) to the point (h, k) is ...
(d₁)² = (x-h)²+(y-k)²
The expression for the square of the distance from (x, y) to the directrix line is
(d₂)² = (ax+by+c)²/(a²+b²)

Equating these expressions gives the equation of the parabola.
(x-h)²+(y-k)² = (ax+by+c)²/(a²+b²)

When the directrix is parallel with one of the axes, one of the coefficents "a" or "b" is zero and the equation becomes much simpler. Often, it would be easier to make use of the formula (for a directrix parallel to the x-axis):
y = 1/(4p)*(x -h)² +k
where the (h, k) here is the vertex, the point halfway between the focus and directrix, and "p" is the (signed) distance from the focus to the vertex. (p is positive when the focus is above or to the right of the vertex.)

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2 years ago