Given:
In triangle GHJ, ∠G = 110°, ∠J = 40° and ∠H = 30°.
To find:
The answer to complete the given statements.
Solution:
According to triangle side and angle relationship, largest angle has longest opposite side and smallest angle has shortest opposite side.
∠G = 110°, ∠J = 40° and ∠H = 30°.
Here, ∠G > ∠J = 40° and ∠G > ∠H. So, ∠G is the Largest angle.
Since angle G is largest angle, the opposite side, JH, is longest.
Clearly,
110° > 40° > 30°.
∠G > ∠J > ∠H
Using triangle side and angle relationship, we get
JH > GH > GJ
The order of the side lengths from longest to shortest is JH, GH ahd GJ.
Answer:
Step-by-step explanation:
The constant term of x^2 + 13x – 48 factors into either (3)(-16) or (-3)(16).
Note how 16 - 3 = 13, which is the coefficient of the middle term. Thus, the factors are
(x + 16)(x - 3) which is equivalent to x^2 + 16x - 3x - 48, or x^2 + 13x - 48.
Answer:
- 5.8206 cm
- 10.528 cm
- 23.056 cm^2
Step-by-step explanation:
(a) The Law of Sines can be used to find BD.
BD/sin(48°) = BD/sin(50°)
BD = (6 cm)(sin(48°)/sin(60°)) ≈ 5.82064 cm
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(b) We can use the Law of Cosines to find AD.
AD^2 = AB^2 +BD^2 -2·AB·BD·cos(98°) . . . . . angle ABD = 48°+50°
AD^2 ≈ 110.841
AD ≈ √110.841 ≈ 10.5281 . . . cm
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(c) The area of ∆ABD can be found using the formula ...
A = ab·sin(θ)/2 . . . . . where a=AB, b=BD, θ = 98°
A = (8 cm)(5.82064 cm)sin(98°)/2 ≈ 23.0560 cm^2
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Angle ABD is the external angle of ∆BCD that is the sum of the remote interior angles BCD and BDC. Hence ∠ABD = 48° +50° = 98°.
Answer:
For this case, the first thing we must do is define variables:
x: number of hammers
y: number of wrenches
We write the system of inequations:
10x + 6y <= 120
x + y> = 14
Step-by-step explanation:
Answer:
500 calories
Step-by-step explanation:
divide the 1250 calories by the initial five servings and you get 250 then multiply that by the 2 servings they are asking for and you get 500 calories
