V=basearea times 1/3 times height
basearea=6<span>4π m2
hmm, they try to make it difficult
basearea=circle=pir^2
pir^2=64pi
divide by pi
r^2=64
sqrt
r=9
h is 4 les than 3 time r
h=-4+3(8)
h=-4+24
h=20
v=1/3*64pi*20=1280pi/3 m^3=1350.4
C
</span>
Answer:
The answer is C. Lila made an error in Step 3 when she did not use the x- and y-coordinates from the same ordered pair.
Hope this helps!
Stay safe at home :)
(those of you doing edge hang in there!)
To see the effect on Robertos balance sheet, we will first have to get the total assets and liabilities
Total assets = cash+ investment+ house + car
Total liabilities= credit card + personal loan + mortgage + car loan
Substituting the values, we will get
Total asset =$166000
Total liabilities =$1010000
Difference= $844000
To pay off car loan, he uses his investment
Total asset = $166000-5000
=$161000
Total liabilities= $1010000-5000
=$1005000
Difference=$844000
Therefore the answer is letter C, the difference between asset and liability will remain the same.
Answer:
We want a polynomial of smallest degree with rational coefficients with zeros in
,
and -3. The last root gives us the factor (x+3). Hence, our polynomial is

where
is a polynomial with rational coefficients and roots
and
. The root
gives us a factor
, but in order to obtain rational coefficients we must consider the factor
.
An analogue idea works with
. For convenience write
. This gives the factor
. Hence,

Notice that
. So, in order to satisfy the last condition we divide by 3 the whole polynomial, without altering its roots. Finally, the wanted polynomial is

Step-by-step explanation:
We must have present that any polynomial it's determined by its roots up to a constant factor. But here we have irrational ones, in order to eliminate the irrational coefficients that a factor of the type
will introduce in the expression, we need to multiply by its conjugate
. Hence, we will obtain
that have rational coefficients. Finally, the last condition is given with the intention to fix the constant factor. Usually it is enough to evaluate in the point and obtain the necessary factor.