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2 years ago

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A ferry traveled \dfrac16 6 1 start fraction, 1, divided by, 6, end fraction of the distance between two ports in \dfrac37 7 3

start fraction, 3, divided by, 7, end fraction hour. The ferry travels at a constant rate. At this rate, what fraction of the distance between the two ports can the ferry travel in one hour?

2 answers:

Ugo [173]2 years ago

5 0

Answer:

<em>The ferry can travel $\frac{7}{18}$ of the distance between the two ports in one hour.</em>

Step-by-step explanation:

A ferry traveled $\frac{1}{6}$ of the distance between two ports in $\frac{3}{7}$ hour.

Suppose, the ferry traveled $x$ of the distance between the two ports in one hour.

So, the <u>equation according to the ratio of "distance" to "time"</u> will be.......

$\frac{\frac{1}{6}}{\frac{3}{7}} =\frac{x}{1} \\ \\ x=\frac{1}{6}\times \frac{7}{3}= \frac{7}{18}$

Thus, the ferry can travel $\frac{7}{18}$ of the distance between the two ports in one hour.

3241004551 [841]2 years ago

5 0

Answer:

7/18

Step-by-step explanation:

if it is in khanacademy it's 7/18

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The procedure is as follows:

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Answer:

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Step-by-step explanation:

The given conic has equation:

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The hyperbola has been translated from the origin to (0,5).

The translated hyperbola will have equation;

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Expand

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The second question:

Consider the division expression $7\frac{1}{2} / 2$ . Select all multiplication equations that correspond to this division expression.

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$2* 7\frac{1}{2} = ?$ $? * 7\frac{1}{2} = 2$

Answer:

1. See Explanation

2. $2 * ? = 7\frac{1}{2}$ and $? * 2 = 7\frac{1}{2}$

Step-by-step explanation:

Solving (a):

Given

$Students = 60$

$Group = Equal\ Sized$

Required

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<u>Interpretation 1:</u> Number of groups if there are 5 students in each

<u>Interpretation 2:</u> Number of students in each group if there are 5 groups

<u>Solving the quotient</u>

$Quotient = \frac{60}{5}$

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The quotient means: 12 groups

<u>For Interpretation 2:</u>

The quotient means: 12 students

Solving (b):

Given

$7\frac{1}{2} / 2$

Required

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Apply commutative law of addition:

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