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andrew-mc [135]
2 years ago
6

According to government​ data, the probability that an adult was never in a museum is 10​%. In a random survey of 60 ​adults, wh

at is the mean and standard deviation of the number that were never in a​ museum? Round to the nearest thousandth.
Mathematics
1 answer:
lutik1710 [3]2 years ago
5 0

Answer:

\text{Mean}=)=6\\\\\text{Standard deviation}=2.324

Step-by-step explanation:

Given : The probability that an adult was never in a museum is : p=0.10

The number of adults randomly surveyed: n = 60

In Binomial distribution , the formula to find the mean and the standard deviation is given by :-

\text{Mean}=np\\\\\text{Standard deviation}=\sqrt{np(1-p)}

Then , the mean and standard deviation of the number that were never in a​ museum will be :-

\text{Mean}=60(0.10)=6\\\\\text{Standard deviation}=\sqrt{60(0.10)(1-0.1)}=2.3237900077\approx2.324

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