Question

According to government​ data, the probability that an adult was never in a museum is 10​%. In a random survey of 60 ​adults, what is the mean and standard deviation of the number that were never in a​ museum? Round to the nearest thousandth.

Answer 1

Answer:

$\text{Mean}=)=6\\\\\text{Standard deviation}=2.324$

Step-by-step explanation:

Given : The probability that an adult was never in a museum is : p=0.10

The number of adults randomly surveyed: n = 60

In Binomial distribution , the formula to find the mean and the standard deviation is given by :-

$\text{Mean}=np\\\\\text{Standard deviation}=\sqrt{np(1-p)}$

Then , the mean and standard deviation of the number that were never in a​ museum will be :-

$\text{Mean}=60(0.10)=6\\\\\text{Standard deviation}=\sqrt{60(0.10)(1-0.1)}=2.3237900077\approx2.324$