G=4cm-3m solve for m

John's commute to work is 20kmhr while Sheri's commute is 500mmin. Who has the fastest commute to work in mihrif 1.61km=1mi? A S

Andreyy89

Answer:

A) Sheri has the faster commute by 6.2 miles/hr.

Step-by-step explanation:

Given

John's commute to work $=20\ km/hr$

Sheri's commute to work $=500\ m/min$

$1.61\ km = 1\ mile$

John's commute to work in miles per hour = $\frac{20\ km}{1 hr}\times \frac{1\ mile}{1.61\ km}= 12.42\ miles/hr$

Sheri's commute to work in miles per hour = $\frac{500\ m}{1\ min}\times \frac{1\ km}{1000\ m}\times \frac{1\ mile}{1.61\ km}\times \frac{60\ min}{1\ hr}= 18.63\ miles/ hr$

We can see that Sheri has a faster commute.

Difference between the rates = $18.63\ miles/ hr-12.42\ miles/hr=6.21\ miles/hr\approx 6.2\ miles/hr$

∴ Sheri has the faster commute by 6.2 miles/hr.

3 0

2 years ago

Kevin has had a checking account for a month. As he reconciles his account, Kevin notices that the dates on his check register d

Anika [276]

The most likely answer is D) "The date that the check is written is usually a few days before it is cashed. We record when it was cashed and you record when its written".

There is usually a delay between when you write someone a check (and record it in your ledger) and when that person cashes it (when the bank records it).

7 0

2 years ago

The drama club at Del Rosa Middle School is having a production.

Firdavs [7]

Answer:

320 Student Tickets

180 Adult Tickets

Step-by-step explanation:

You can solve this problem by using system of equations. First, we need to figure out our equations.

Equation 1: x as students and y as adults

$x+y=500$

We get this equation because the total tickets sold was 500. The x represents the students sold to students, and the y represents the tickets sold to adults.

Equation 2:

$3x+5y=1850$

We get this equation based on the prices. Each student ticket costs $3, and each adult ticket costs $5. The total amount earned was $1850.

Now that we have out equations, we can use system of equations to find our students and adults.

$x+y=500$

$3x+5y=1860$

Typically elimination is the easiest strategy because you are able to cross out variables.

$3(x+y=500)$

$3x+5y=1860$

Becomes:

$3x+3y=1500$

$3x+5y=1860$

We see that both equations now have 3x. We can cancel out 3x.

$-2y=-360$

$y=180$

Now that we know y=180, we can plug it back into one of our equations to find x.

$x+180=500$

$x=320$

320 student tickets and 180 adult tickets were sold.

6 0

2 years ago

A baker uses 13 1/2 cups of flour to make bread. She uses 2 1/4 cups of flour to make each loaf. The baker sells 2/3 of the loav

ollegr [7]

Answer:

She sells 4 loaves of bread

Step-by-step explanation:

Lets explain how to solve the problem

→ A baker uses $13\frac{1}{2}$ cups of flour to make bread

→ She uses $2\frac{1}{4}$ cups of flour to make each loaf

From these information we can find the number of loaves of bread

she can make

∵ There are $13\frac{1}{2}$ cups of flour

∵ Each loaf of bread needs $2\frac{1}{4}$ cups of flour

∴ The number of loaves = $13\frac{1}{2}$ ÷ $2\frac{1}{4}$

To divide two mixed numbers make them improper fractions and

change the division sign to multiplication sign and reciprocal the

fraction after the division sign

∵ $13\frac{1}{2}$ = $\frac{(13)(2)+1}{2}$

∴ $13\frac{1}{2}$ = $\frac{27}{2}$

∵ $2\frac{1}{4}$ = $\frac{(2)(4)+1}{4}$

∴ $2\frac{1}{4}$ = $\frac{9}{4}$

∴ The number of loaves = $\frac{27}{2}$ × $\frac{4}{9}$

∴ The number of loaves = 6

She can make 6 loaves

→ The baker sells $\frac{2}{3}$ of the loaves of bread that she makes

→ We need to find the number of loves of bread she sells

∵ She sells $\frac{2}{3}$ of the loaves

∵ There are 6 loves

∴ The number of loaves she sells = 6 × $\frac{2}{3}$ = 4

She sells 4 loaves of bread

7 0

2 years ago

Bones Brothers & Associates prepare individual tax returns. Over prior years, Bones Brothers have maintained careful records

madreJ [45]

Answer:

For this case we have the following info related to the time to prepare a return

$\mu =90 , \sigma =14$

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation would be:

$\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2$

And the best answer would be

b. 2 minutes

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

For this case we have the following info related to the time to prepare a return

$\mu =90 , \sigma =14$

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation would be:

$\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2$

And the best answer would be

b. 2 minutes

3 0

2 years ago