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Elden [556K]
2 years ago
15

A public interest group hires students to solicit donations by telephone. After a brief training period students make calls to p

otential donors and are paid on a commission basis. Experience indicates that early​ on, these students tend to have only modest success and that 80​% of them give up their jobs in their first two weeks of employment. The group hires 7 ​students, which can be viewed as a random sample.
Mathematics
1 answer:
IceJOKER [234]2 years ago
8 0
I need help with the answer?
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Let Y denote a geometric random variable with probability of success p. a Show that for a positive integer a, P(Y > a) = qa .
lakkis [162]

Answer:

a) For this case we can find the cumulative distribution function first:

F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k

So then by the complement rule we have this:

P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a

b) P(Y>a)= q^a

P(Y>b) = q^b

So then we have this using independence:

P(Y> a+b) = q^{a+b}

We want to find the following probability:

P(Y> a+b |Y>a)

Using the definition of conditional probability we got:

P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)

And we see that if a = 2 and b=5 we have:

P(Y> 2+5 | Y>2) = P(Y>5)

c) For this case we use independent identical and with the same distribution experiments.

And the result for part b makes sense since we are interest in find the probability that the random variable of interest would be higher than an specified value given another condition with a value lower or equal.

Step-by-step explanation:

Previous concepts

The geometric distribution represents "the number of failures before you get a success in a series of Bernoulli trials. This discrete probability distribution is represented by the probability density function:"

P(X=x)=(1-p)^{x-1} p

If we define the random of variable Y we know that:

Y\sim Geo (1-p)

Part a

For this case we can find the cumulative distribution function first:

F(k) = P(Y \leq k) = \sum_{k'=1}^k P(Y =k')= \sum_{k'=1}^k p(1-p)^{k'-1}= 1-(1-p)^k

So then by the complement rule we have this:

P(Y>a) = 1-F(a)= 1- [1-(1-p)^a]= 1-1 +(1-p)^a = (1-p)^a = q^a

Part b

For this case we can use the result from part a to conclude that:

P(Y>a)= q^a

P(Y>b) = q^b

So then we have this assuming independence:

P(Y> a+b) = q^{a+b}

We want to find the following probability:

P(Y> a+b |Y>a)

Using the definition of conditional probability we got:

P(Y> a+b |Y>a)= \frac{P(Y> a+b \cap Y>a)}{P(Y>a)} = \frac{P(Y>a+b)}{P(Y>a)} = \frac{q^{a+b}}{q^a} = q^b = P(Y>b)

And we see that if a = 2 and b=5 we have:

P(Y> 2+5 | Y>2) = P(Y>5)

Part c

For this case we use independent identical and with the same distribution experiments.

And the result for part b makes sense since we are interest in find the probability that the random variable of interest would be higher than an specified value given another condition with a value lower or equal.

8 0
2 years ago
Find the CP of the following Sp=Rs 851 , Loss=8%​
elena55 [62]
<h2> Heya </h2>

<h3>Selling Price = Rs. 851</h3>

<h3>Loss = 8%</h3>

<h3>FORMULA = 100/100 - LOSS % × SP</h3>

<h3>CP = 100/100 - 8 × 851</h3>

<h3> CP = 100/92 × 851</h3>

<h3> CP = Rs. 925</h3>

<h3>HOPE IT HELPS YOU.</h3>
8 0
2 years ago
Sequence 1.5,3.9,6.3,8.7
Nitella [24]
Lololollolollllollllolloolollllll IM TRYING TO GET POINTS. THX
7 0
2 years ago
Read 2 more answers
What is the measure of Arc W U X in circle V?
lukranit [14]

Answer:

30

Step-by-step explanation:

i had the same test xD

6 0
2 years ago
F(x)=3x 2 +24x+48f, left parenthesis, x, right parenthesis, equals, 3, x, squared, plus, 24, x, plus, 48 What is the value of th
neonofarm [45]

Answer:

The discriminant of function is 0. There one distinct real number zero of f(x)(repeated roots).

Step-by-step explanation:

We are given the following function in the question:

f(x)=3x^2 +24x+48

We have to calculate the discriminant of the function.

Comparing to

f(x) = ax^2+bx+c

We get,

a = 3\\b=24\\c = 48

Discriminant is given by:

D = b^2-4ac

Putting values, we get,

D = (24)^2-4(3)(48) = 0

Thus, the discriminant of function is 0.

Since, the discriminant is zero, the function have repeated real roots. Thus, one distinct real number zero of f(x).

3 0
2 years ago
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