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maw [93]
2 years ago
14

a rectangle rug has a perimeter of 146 ft the width of the rug is 5 feet more than three times the length find the length and th

e width​
Mathematics
2 answers:
dem82 [27]2 years ago
7 0

Answer:

The length = 56 feet and the width = 17 feet.

Step-by-step explanation:

We can set up 2 equations to solve this. Let the length of the rug be x, then

x = 3w + 5    where w = the width.   ( looks like you got the width and the length mixed up. The length is the longest side)

The perimeter = 2x + 2w = 146 so we have the 2 equations:

x = 3w + 5

2x + 2w = 146

Now we substitute for x in the second equation:

2(3w + 5) + 2w = 146

6w + 10 + 2w = 146

8w = 136

w = 17 feet,

and x = 3(17) + 5 =  56 feet.

Aleksandr [31]2 years ago
3 0

Answer:

Length is 17 feet and Width is 56 feet.

Step-by-step explanation:

P=2L+2W

146=2L+2(3L+5)

146=2L+6L+10

146=8L+10L

146-10=8L+10-10

136=8L

136\8=8\8

17=L

W=3L+5

  =3(17)+5

  =56

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Answer:

27

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2 years ago
The cost for children under twelve at a certain buffet restaurant is a base charge of a dollar plus twenty-five cents for each y
Nady [450]

Answer:

Cost = 1 + 0.25y

Cost =3.25

Step-by-step explanation:

Given

Base\ Amount = \$ 1

Additional = 25cents of child's age

Solving (1):

Determine the cost function.

Represent the years as y.

So, we have:

Additional = 25cents * y

Convert 25 cents to dollars.

25 cents = 25 * \$0.01

25 cents = \$0.25

So, we have:

Additional = \$0.25 * y

The cost amount is then:

Cost = Base\ Amount + Additional

Cost = 1 + 0.25y --- This is the cost function

Solving (b): Cost of 9 years old.

In this case;

y = 9

Substitute 9 for y in Cost = 1 + 0.25y

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4 0
2 years ago
Construct a table of values for the following functions using the integers from -4 to 4.
jeka57 [31]

Step-by-step explanation:

Find the table attached

a) Given

F(x) = 6/x-2

When x = -4

F(-4) = 6/-4-2

F(-4) = 6/-6

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F(x) = 6/x-2

When x = -3

F(-3) = 6/-3-2

F(-3) = 6/-5

F(-3) = -1.2

F(x) = 6/x-2

When x = -2

F(-2) = 6/-2-2

F(-2) = 6/-4

F(-2) = -1.5

F(x) = 6/x-2

When x = -1

F(-1) = 6/-1-2

F(-1) = 6/-3

F(-1) = -2.0

F(x) = 6/x-2

When x = 0

F(0) = 6/0-2

F(0) = 6/-2

F(0) = -3

F(x) = 6/x-2

When x = 1

F(1) = 6/1-2

F(1) = 6/-1

F(1) = -6

F(x) = 6/x-2

When x = 2

F(2) = 6/2-2

F(2) = 6/0

F(2) = infty

F(x) = 6/x-2

When x = 3

F(3) = 6/3-2

F(3) = 6/1

F(3) = 6

F(x) = 6/x-2

When x = 4

F(4) = 6/4-2

F(4) = 6/2

F(4) = 3

b) Given

r(x)=6x+12/x^-4

When x = -4

r(-4) = 6(-4)+12/(-4)^-4

r(-4) = -24+12/(1/256)

r(-4) = -12(256)

r(-4) = -3072

When x = -3

r(-3) = 6(-3)+12/(-3)^-4

r(-3) = -18+12/(1/81)

r(-3) = -6(81)

r(-3) = -486

When x = -2

r(-2) = 6(-2)+12/(-2)^-4

r(-2) = -12+12/(1/16)

r(-2) = -0(16)

r(-2) = 0

When x = -1

r(-1) = 6(-1)+12/(-1)^-4

r(-1) = -6+12/(1)

r(-1) = -6+12

r(-1) = 6

When x = 0

r(0) = 6(0)+12/(0)^-4

r(0) = 0+12/0

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r(0) = infty

When x = 1

r(1) = 6(1)+12/(1)^-4

r(1) = 6+12/1

r(1) = 18(1)

r(1) = 18

When x = 2

r(2) = 6(2)+12/(2)^-4

r(2) = 12+12/1/16

r(2) = 24(16)

r(2) = 384

When x = 3

r(3) = 6(3)+12/(3)^-4

r(3) = 18+12/1/81

r(3) = 30(81)

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r(4) = 6(4)+12/(4)^-4

r(4) = 24+12/1/256

r(4) = 36(256)

r(4) = 9216

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so,
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z = 1.645 (Z value for 90% confidence interval)

The margin of error for population proportion is calculated as:

E=z* \sqrt{ \frac{p(1-p)}{n} }  \\  \\ 
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