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Sati [7]
1 year ago
9

Haley is considering two gym membership plans. The plans are detailed here. Plan one $50 for a monthly pass and a $3 fee for eac

h gym visit plan to $10 for each gym visit what is a system of equations that represents the cost of the plans?
Mathematics
2 answers:
Alona [7]1 year ago
8 0

Answer:

The system of equations would be

\left \{ {{50+3x=y} \atop {10x=y}} \right.

Step-by-step explanation:

Let x represent the number of gym visits and y represent the total cost.

For plan one, we know that each gym visit is $3.  This means the price for the gym visits can be represented as 3x.  Adding the monthly pass to that, we have

50+3x = y.

For plan two, each gym visit is $10.  This means the price of the gym visits can be represented as 10x.  There is no monthly pass, so we have the equation

10x = y.

vodomira [7]1 year ago
5 0
Well for the first one it'd be y=3x+50 and for the second one it'd be y=10x
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Lera brought a watermelon that weighed b kg to a party. Nick brought a box of candies. How much is the weight of the box of cand
Dennis_Churaev [7]

Answer:

1.5b (kg)

Step-by-step explanation:

Let's begin by listing out the variables we were given:

weight of the watermelon = b (kg),

weight of watermelon = (2/5) * weight of candies

weight of candies = 1 ÷ (2/5) = 1 ÷ 0.4

weight of candies = 2.5b (kg)

How much is the weight of the box of candies greater than the weight of the watermelon is given by:

weight of the box of candies - weight of watermelon= 2.5b - b = <u>1.5b</u> (kg)

<u>Therefore, the weight of the box of candies is greater than the weight of the watermelon by 1.5b (kg) </u>

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2 years ago
Find the standard form equation of an ellipse with a focus at the origin and the point 4,2 on the latus rectum
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2 years ago
The coordinates of the vertices of quadrilateral ABCD are A(−6, 3) , B(−1, 5) , C(3, 1) , and D(−2, −2) . Which statement correc
Pavlova-9 [17]

Answer:

C.Quadrilateral ABCD is not a rhombus because there are no pairs of parallel sides.

Complete question:

A. Quadrilateral ABCD is not a rhombus because opposite sides are parallel but the four sides do not all have the same length.

B. Quadrilateral ABCD is a rhombus because opposite sides are parallel and all four sides have the same length.

C. Quadrilateral ABCD is not a rhombus because there are no pairs of parallel sides.

D. Quadrilateral ABCD is not a rhombus because there is only one pair of opposite sides that are parallel.

Step-by-step explanation:

Rhombus states that a parallelogram with four equal sides and sometimes one with no right angle.

Given: The coordinate of the vertices of quadrilateral ABCD are A(−6, 3) , B(−1, 5) , C(3, 1) , and D(−2, −2) .

The condition for the segment (x_{1},y_{1}), (x_{2},y_{2})  to be parallel to (x_{3},y_{3}),  (x_{4},y_{4}) is matching slopes;

\frac{y_{2}-y_{1}}{x_{2}-x_{1}}= \frac{y_{4}-y_{3}}{x_{4}-x_{3}} \\(y_{2}-y_{1}) \cdot (x_{4}-x_{3}) =(y_{4}-y_{3}) \cdot (x_{2}-x_{1})---->1

So, we have to check that AB || CD and AD || BC

First check AB || CD

A(−6, 3) , B(−1, 5) , C(3, 1) , and D(−2, −2)

substitute in [1],

(5-3) \cdot (-2-3) = (-2-1) \cdot (-1-(-6))2 \cdot -5 = -3 \cdot 5

-10 ≠ -15

Similarly,

check AD || BC

A(−6, 3) , D(−2, −2) , B(−1, 5) and C(3, 1)

Substitute in [1], we have

(-2-3) \cdot (3-(-1)) = (1-5) \cdot (-2-(-6))-5 \cdot 4 = -4 \cdot 4

-20 ≠ -16.

Both pairs of sides are not parallel,

therefore, Quadrilateral ABCD is not a rhombus because there are no pairs of parallel sides.

8 0
2 years ago
Solve the system of equations. -9Y +4X -20 =0<br> -7Y +16 X -80 =0<br> X=<br> Y=
Fofino [41]

Answer:

X=5, Y=0

Step-by-step explanation:

-9Y +4X -20=0

-7Y+16X-80=0

1. We can multiply the first equation by 4. This will equal to -36Y +16X-80=0.

-36Y +16X -80 =0

-7Y+16X-80=0

2.  We can subtract these two equations.

-36Y +16X -80 =0

-7Y+16X-80=0

We will get -29Y =0. Y=0.

3. Then we can substitute y into the first equation. -9(0) +4x-20 =0. 4x=20. x=5

X=5, Y=0

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1 year ago
Circle A has been dissected into 16 congruent sectors. The base of one sector is 1.95 units, and its height is 4.9 units. What i
stira [4]

Answer:

A=76.44\ units^{2}

Step-by-step explanation:

To find the approximate area of the circle, calculate the area of one sector and then multiply by 16

Remember that

The area of a triangle (one sector) is equal to

A=\frac{1}{2}(b)(h)

therefore

The approximate area of the circle is equal to

A=(16)\frac{1}{2}(1.95)(4.9)

A=76.44\ units^{2}

3 0
2 years ago
Read 2 more answers
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