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larisa [96]
2 years ago
6

Use this information to find the value of b.c = 25s = 9b = 4c - s2

Mathematics
1 answer:
Travka [436]2 years ago
3 0
Hello There!

Write out the formula again:
b = 4c - s².
Substitute your numbers in:
b = 4(25) - (9)²
Simplify:
4 x 25 = 100
9² = 81
b = 100 - 81
Solve:
100 - 81 = 19
b = 19.

Hope This Helps You!
<span>Good Luck :) </span>

<span>- Hannah ❤</span>
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Simplify 2(3×8-15÷16)<br>​
KengaRu [80]

Answer:

46.125 or 46 1/8

Step-by-step explanation:

2(3×8-15÷16)

=2(24-15÷16)

= 48 - 30/16

= (768 - 30)/16

= 738/16

= 46.125 or 46 1/8

8 0
2 years ago
t takes Dariya 35 seconds to download 5 songs from the Internet. How can the number of seconds it would take Dariya to download
Vitek1552 [10]
She would be able to download 49 at this rate.
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8 0
2 years ago
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If a diameter of a circle with a circumference of 104.48 mm is reduced by 1/2,what is the circumference of the new circle?
klio [65]
All we need to do here is divide the circumference by 2.

104.48 / 2 = 52.24

The new circumference is 52.24 mm.
4 0
2 years ago
How many marbles, each with a volume of 36 cubic centimeters, are needed to fill in a cylindrical vase with a radius of 6 centim
ANEK [815]
The volume of a cylinder can be found using the formula:

π r² h, 

where r is the radius of the circular base and h is the height of the cylinder.

If we plug in the measurements of the cylinder, we get:

π (6²) (28)

When this is simplified, we get that the volume of the cylinder is:

1008π cubic cm

Thus, if each marble has a volume of 36π cubic cm, then to find how many marbles will fit into the vase we must divide the vases total volume by the volume of each marble.

1008π / 36π = 28

Therefore, the answer is D. 28 marbles
7 0
2 years ago
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Let Xn be the random variable that equals the number of tails minus the number of heads when n fair coins are flipped. What is t
Firlakuza [10]

Answer:

the expected value of Xn , E(Xn) = 0 and the variance σ²(Xn) = n*(1-2n)

Step-by-step explanation:

If X1= number of tails when n fair coins are flipped , then X1 follows a binomial distribution with E(X1) = n*p , p=0,5 and the number of heads obtained is X2=n-X1

therefore

Xn =X1-X2 = X1- (n-X1) = 2X1-n

thus

E(Xn) =∑ (2*X1-n) p(X1) =  2*∑[X1 p(X1)] -n∑p(X1) = 2*E(X1)-n = 2*n*p--n= 2*n*1/2 -n = n-n =0

the variance will be

σ²(Xn) = ∑ [Xn - E(Xn)]² p(Xn) = ∑ [(2X1-n) - 0 ]² p(X1) = ∑ (4*X1²-4*X1*n+n²) p(X1) = = 4*∑ X1²p(X1) - 4n ∑X1 p(X1) -  n²∑p(X1) = 2*E(X1²) -4n*E(X1)- n²

since

σ²(X1) = n*p*(1-p) = n*0,5*0,5=n/4

and

σ²(X1) = E(X1²) - [E(X1)]²

n/4 = E(X1²) - (n/2)²

E(X1²) = n(n+1)/4

therefore

σ²(Xn) = 4*E(X1²) -4n*E(X1)- n² = 4*n(n+1)/4 - 4*n*n/2 - n² = n(n+1) - 2n² - n²

= n - 2n² = n(1-2n)

σ²(Xn) = n(1-2n)

4 0
1 year ago
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