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Andreyy89
2 years ago
15

Seventy cards are numbered 1 through 70, one number per card. One card is randomly selected from the deck. What is the probabili

ty that the number drawn is a multiple of 3 AND a multiple of 5?
Mathematics
1 answer:
miskamm [114]2 years ago
7 0

Given:

Seventy cards are numbered 1 through 70, one number per card. One card is randomly selected from the deck.

To find:

The probability that the number drawn is a multiple of 3 and a multiple of 5.

Solution:

Total number from 1 to 70 = 70

Multiple of 3 from 1 to 70 are 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63, 66, 69.

Multiple of 5 from 1 to 70 are 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70.

Numbers which are multiply of both number 3 and 5 = 15, 30, 45, 60

Number of favorable outcomes = 4

Probability=\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}

Probability=\dfrac{4}{70}

Probability=\dfrac{2}{35}

Therefore, the required probability is \dfrac{2}{35}.

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Answer:

n(A) = n_1A^k

Step-by-step explanation:

Taking into account that the growth rate of the number of species on the island is proportional to the density of species (number of species between area of the island), a model based on a differential equation is proposed:

\frac{dn}{dA} = k\frac{n}{A}

This differential equation can be solved by the method of separable variables like this:

\frac{dn}{n} = k\frac{dA}{A} with what you get:

\int\ {\frac{dn}{n}}\ = k\int\ {\frac{dA}{A}}

ln|n| = kln|A|+C. Taking exponentials on both sides of the equation:

e^{ln|n|} = e^{ln|A|^{k}+C}

n(A) = e^{C}A^{k}

how do you have to n (1) = n_1, then

n(A) = n_1A^k

8 0
2 years ago
A poll found that 5% of teenagers (ages 13 to 17) suffer from arachnophobia and are extremely afraid of spiders. At a summer cam
brilliants [131]

Answer:

a) Calculate the probability that at least one of them suffers from arachnophobia.

x = number of students suffering from arachnophobia

= P(x ≥ 1)

= 1 - P(x = 0)

= 1 - [0.05⁰ x (1 - 0.05)¹¹⁻⁰ ]

= 1 - (0.95)¹¹

= 0.4311999 = 0.4312

b) Calculate the probability that exactly 2 of them suffer from arachnophobia? 0.08666

=  P(x = 2)

=  (¹¹₂) x (0.05)² x (0.95)⁹

where ¹¹₂ = 11! / (2!9!) = (11 x 10) / (2 x 1) = 55

= 55 x 0.0025 x 0.630249409 = 0.086659293 = 0.0867

c) Calculate the probability that at most 1 of them suffers from arachnophobia?

P(x ≤ 1)

= P(x = 0) + P(x = 1)    

= [(¹¹₀) x 0.05⁰ x 0.95¹¹] + [(¹¹₁) x 0.05¹ x 0.95¹⁰]

= (1 x 1 x 0.5688) + (11 x 0.05 x 0.598736939) = 0.5688 + 0.3293 = 0.8981

4 0
2 years ago
Luca had a large container of yogurt with 1 and StartFraction 5 Over 8 EndFraction pounds of yogurt left in it. If a serving of
lisov135 [29]

Answer:

4 servings

Step-by-step explanation:

Yogurt in the container = 1 5/8 pounds

A serving = 3/8 pounds

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Servings in the yogurt container = total yogurt in the container / yogurt per servings

= 1 5/8 ÷ 3/8

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2 years ago
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The slope-intercept form of a linear equation is y = mx + b, where x and y are coordinates of an ordered pair, m is the slope of
anzhelika [568]

We have been given that the slope-intercept form of a linear equation is y = mx+b, where x and y are coordinates of an ordered pair, m is the slope of the line, and b is where the line crosses the y-axis. We are asked to solve the equation for slope.

First of all, we will subtract 'b'from both sides.

y-b= mx+b-b

y-b= mx

Let us switch the sides:

mx=y-b

Now we will divide both sides by x.

\frac{mx}{x}=\frac{y-b}{x}

m=\frac{y-b}{x}

Therefore, the value of m is \frac{y-b}{x}.

7 0
2 years ago
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