Answer:
-4g-3
------------
g+2
Step-by-step explanation:
g+1 5g+4
------------- - ------------------
g+2 g+2
Since the denominators are the same, subtract the numerators
g+1 - (5g+4)
Distribute the negative sign
g+1 -5g-4
-4g-3
Put this back over the denominator
-4g-3
------------
g+2
<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
</span>
<span>

.
</span>
{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>

Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
<span /><span>
</span><span>
</span>

.
He should have worked out 7h(2 - h) first before adding the 3h. (first step)
2nd step he multiplied the 2 by -10h but he also should have multiplied the -h by the -10h ( Distributive law)
Answer:
115° and 245°
Step-by-step explanation:
Given
cos x = - 0.4226
Since cos x < 0 then x is an angle in the second / third quadrants, thus
x = (0.4226) = 65° ← related acute angle , thus
x = 180° - 65° = 115° ← angle in second quadrant
x = 180° + 65° = 245° ← angle in third quadrant