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k0ka [10]
2 years ago
10

Hazel covered a box with felt. The dimensions of the box are shown in the figure below:

Mathematics
1 answer:
maria [59]2 years ago
8 0

<span>$36.36 because the area of the prism is 404sq. in. , 404x0.09 (for nine cents per sq. in.) = 36.36
</span>
Hope this helps!! :)
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The image shows parallel lines cut by a transversal. The expressions represent unknown angle measurements. What is the value of
Anna35 [415]

Answer:

x = 8

Step-by-step explanation:

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2 years ago
t​ Technodynamics, Inc., a​ randomly-selected hiring committee of 3 people is formed from a group of 4 employees in marketing an
atroni [7]

Answer: a) 0.25, b) 0.78, c) 0.71

Step-by-step explanation:

Since we have given that

Number of employees in marketing = 4

Number of employees in management = 7

We need to hire committee of 3 people.

​a) Find the probability that the committee has exactly 2 employees from marketing.

So, Probability becomes

\dfrac{^4C_2\times ^7C_1}{^{11}C_3}\\\\=\dfrac{42}{165}\\\\=0.25

​b) Find the probability that the committee has at least one employee from marketing.

P(x\geq 1)=1-P(x=0)\\\\P(x\geq 1)=1-\dfrac{^7C_3}{^{11}C_3}=1-0.212=0.78

c) Find the probability that the committee has at most one employee from management.

P(x\leq 1)=P(x=0)+P(x=1)\\\\P(x\leq 1)=\dfrac{^7C_3}{^{11}C_3}+\dfrac{^7C_2\times ^4C_1}{^{11}C_3}\\\\P(x\leq 1)=0.21+0.50=0.71

Hence, a) 0.25, b) 0.78, c) 0.71

8 0
2 years ago
robert plant 7 trees behind westwood school. he planted 6 times as many trees in front of the school. how many trees did he plan
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49 in total or 42 trees in the front

4 0
2 years ago
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The potential energy, P, in a spring is represented using the formula P = A equals StartFraction one-half EndFraction b h.kx2. L
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Step-by-step explanation:

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2 years ago
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A study of 25 graduates of four-year public colleges revealed the mean amount owed by a student in student loans was $55,051. Th
Kitty [74]

Answer:

a

   The  90%  confidence interval is  52561.13  <  \mu  < 57540.8

b

Confidence interval for the population men between <u>$52561.13</u>  up to <u>$57540.8</u>

Step-by-step explanation:

From the question we are told that

   The sample size is  n = 25

     The  sample mean is  \= x  =  \$ 55,051

     The standard deviation is  \sigma  =  \$ 7,568

Given that the confidence level is  90% then the level of confidence is mathematically represented as

             \alpha  =  100 -90

              \alpha  = 10\%

             \alpha  = 0.10

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table the values is  

               Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically  represented as

               E =  Z_{\frac{ \alpha }{2} } * \frac{ \sigma }{\sqrt{n} }

substituting values

               E =  1.645 * \frac{ 7568}{ \sqrt{ 25} }

             E =  2489.9

The 90% confidence interval is mathematically evaluated as

       \= x  -E  <  \mu  <  \= x  +E

substituting values

     55051  - 2489.8  <  \mu  <  55051  + 2489.8

     52561.13  <  \mu  < 57540.8

6 0
2 years ago
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