Question

Solve for z a(t+z)=45z+67

Answer 1

Solve for z a(t+z)=45z+67
1. Expand
$at+az=45z+67$

2. Subtract $at$ from both sides
$az=45z+67-at$

3. Subtract 45z from both sides
$az-45z=67-at$

4. Factor out the common term z
$z(a-45)=67-at$

5. Divide both sides by a - 45
$z= \frac{67-at}{ya-45}$

Answer: $z= \frac{67-at}{a-45}$

Answer 2

Answer:

The value of the equation for z is $z=\frac{at-67}{45-a}$.  

Step-by-step explanation:

Consider the provided equation.

$a(t+z)=45z+67$

Open the parentheses.

$at+az=45z+67$

Subtract az from both sides.

$at+az-az=45z-az+67$

$at=45z-az+67$

Subtract 67 from both sides.

$at-67=45z-az$

Take z common from right side.

$at-67=z(45-a)$

Divide both the sides by 45-a.

$\frac{at-67}{45-a}=\frac{z(45-a)}{45-a}$

$z=\frac{at-67}{45-a}$

Hence, the value of the equation for z is $z=\frac{at-67}{45-a}$.