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Tom [10]
2 years ago
9

Car A starts in Sacramento at 11am. It travels along a 400 mile route to Los Angeles at 40 mph. Car B starts from Los Angeles at

noon and travels to Sacramento along the same route at 75 mph. The route goes past Fresno which is 150 miles along the route from Los Angeles. How far from Fresno are the cars when they meet?
Mathematics
1 answer:
Naya [18.7K]2 years ago
8 0

Answer:

Distance from Fresno where both cars meet = 210 - 150 = 60 miles

Step-by-step explanation:

let x = distance travelled by A from Sacramento

y = distance travelled by B from Los Angeles

t = time after 12 noon that they meet

x = 50(t + 1)

y = 400 - x = 75(t) or x = 400 - 75t

so: 50(t + 1) = 400 - 75t

     50t + 50 = 400 - 75t

     50t + 75t = 400 - 50

                 t = 2,8 hrs

so y = 400 - 75(2.8) = 210 miles from Los Angeles  

distance from Fresno where both cars meet = 210 - 150 = 60 miles

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Answer: (15.263,\ 17.537)

Step-by-step explanation:

According to the given information, we have

Sample size : n= 50

\overline{x}=16.40

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Since population standard deviation is unknown, so we use t-test.

Critical value for  95 percent confidence interval  :

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16.40\pm (2.010)\dfrac{4}{\sqrt{50}}\\\\=16.40\pm1.13702770415\\\\=16.40\pm1.1370\\\\=(16.40-1.1370,\ 16.40+1.1370)\\\\=(15.263,\ 17.537)

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2 years ago
Katie has 4 grape candies and 3 cherry candies. The ratio of the mumber of grape candies to the total number of candies is what?
dimaraw [331]

Answer 4:7

Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
HELP ASAP!!! (25 points and I’ll mark brainliest!!!!)
defon

Answer:

1. Take the Average of the distances the ball travelled each hit.

2. He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.

3. He should use Mean

4. He should use Median. It best measures skewed data

Step-by-step explanation:

THE FIRST PART.

Raul should take the average of the distances the ball travelled each hit.

This is done by summing the total distances the ball travelled each bounce, and then dividing the resulting value by the total number of times he hit the ball, which is 10.

THE SECOND PART

He should use the Interquartile Range. This is the difference between the Upper Quartile and the Lower Quartile of the distances he hits the ball.

THE THIRD PART

He should take the mean of the distances of the ball that stayed infield.

This is the distance that occurred the most during the 9 bounces that stayed infield. The one that went outfield is makes it unfair to use any other measure of the center, taking the mean will give a value that is significantly below his efforts.

THE FOURTH PART

He should take the Median of the data, it is best for skewed data.

This is the middle value for all the distances he recorded.

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Answer:

A and C

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