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Tom [10]
2 years ago
9

Car A starts in Sacramento at 11am. It travels along a 400 mile route to Los Angeles at 40 mph. Car B starts from Los Angeles at

noon and travels to Sacramento along the same route at 75 mph. The route goes past Fresno which is 150 miles along the route from Los Angeles. How far from Fresno are the cars when they meet?
Mathematics
1 answer:
Naya [18.7K]2 years ago
8 0

Answer:

Distance from Fresno where both cars meet = 210 - 150 = 60 miles

Step-by-step explanation:

let x = distance travelled by A from Sacramento

y = distance travelled by B from Los Angeles

t = time after 12 noon that they meet

x = 50(t + 1)

y = 400 - x = 75(t) or x = 400 - 75t

so: 50(t + 1) = 400 - 75t

     50t + 50 = 400 - 75t

     50t + 75t = 400 - 50

                 t = 2,8 hrs

so y = 400 - 75(2.8) = 210 miles from Los Angeles  

distance from Fresno where both cars meet = 210 - 150 = 60 miles

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Tresset [83]

we know that

1 Kw=1000 w

The company charges 13 cents per kilowatt-hour of electricity

13 cents=0.13 dollars\\\\ 75w=\frac{75}{1000} kw\\\\ 15w=\frac{15}{1000} kw

Step 1

Find the cost for the light bulb

a) in one day

\frac{75}{1000} *12=0.9\ kw\  hour

Cost=0.13*0.9

Cost=$0.117

b) In a year

\frac{75}{1000} *12=0.9\ kw\  hour

0.9*365=328.5\ kw\  hour

Cost=0.13*328.5

Cost=$42.71

Step 2

Find the cost for the led bulb

a) in one day

\frac{15}{1000} *12=0.18\ kw\  hour

Cost=0.13*0.18

Cost=$0.0234

b) In a year

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0.18*365=65.7\ kw\  hour

Cost=0.13*65.7

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Step 3

Find the difference in cost

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therefore

the answer is

34.17 dollars

3 0
2 years ago
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Mrs. Matthews wants to have $18,000 in the bank in 2 years. If she deposits $9000 today at 6% compounded quarterly for 2 years,
OverLord2011 [107]
Depends if you want
1. find how much he will earn, find the differnce between that and 18000
2. see how much to invest till he will  get 18000


A=P(1+ \frac{r}{n})^{nt}

A=futre amount
P=present amout
r=rate in decimal
n=number of times per year ccompounded
t=time in years


1.
A=?
P=9000
r=0.06
n=4 (quarter means 4 times per year)
t=2
?=9000(1+ \frac{0.06}{4})^{(4)(2)}
?=9000(1+ 0.015)^{8}
?=9000(1.015)^{8}
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2.
A=18000
P=9000+x
r=0.06
n=4 (quarter means 4 times per year)
t=2
18000=(9000+x)(1+ \frac{0.06}{4})^{(4)(2)}
18000=(9000+x)(1+ 0.015)^{8}
18000=(9000+x)(1.015)^{8}
divide both sides by 1.015^8
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if he willnot be investing any more, he needs $7861.6 more
if he will invest more he will need to invest $6978.8 more




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2 years ago
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Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
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