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Triss [41]
2 years ago
6

The basketball team sell t-shirts and hats as a fundraiser. they sold a total of 23 items and made a profit of $246. they made a

profit of $10 for every t-shirt they sold and $12 for every hat they sold.
Mathematics
1 answer:
hjlf2 years ago
7 0
S - the number of the t-shirts;
h - the number of hats:
The system of equations:
s + h = 23
10 s + 12 h = 246
--------------------------
s = 23 - h
10 * ( 23 - h ) + 12 h = 246
230 - 10 h + 12 h = 246
2 h = 246 - 230
2 h = 16
h = 16 : 2
h = 8
s = 23 - 8
s = 15
Answer: The basketball team sold 15 t-shirts and 8 hats.

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Goran went for a drive in his new car. he drove for 4 hours at a speed of 25.6 miles per hour. for how many miles did he drive?
Sergio [31]
Distance = Speed * Time

D = 25.6 * 4

D = 102.4 miles

In short, Your Final Answer would be: 102.4 miles

Hope this helps!
8 0
1 year ago
Read 2 more answers
A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un
Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, <em>assuming a significance level 0.1</em>

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

H_{0}:p1=p2

H_{a}:p1≠p2

The formula for the test statistic is given as:

z=\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }  where

  • p1 is the <em>sample</em> proportion of West University students who involved in a car accident within the past year (0.15)
  • p2 is the <em>sample</em> proportion of East University students who involved in a car accident within the past year (0.12)
  • p is the pool proportion of p1 and p2 (\frac{15+12}{100+100}=0.135)
  • n1 is the sample size of the students from West University (100)
  • n2 is the sample size ofthe students from East University (100)

Then we have z=\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } } ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

<em>Assuming significance level 0.1</em>, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

6 0
1 year ago
A recipe calls for 1/4 cup of broth. The largest volume-measuring tool that Tabitha has is a teaspoon. She knows that there are
Lady bird [3.3K]

Answer:

Option b. 12 teaspoons.

Step-by-step explanation:

In the question it given :

1 cup = 16 tablespoons

1 tablespoon = 3 teaspoons

16 tablespoon = 48 teaspoons or 1 cup

A recipe calls for 1/4 cup of broth. Tabitha has only a teaspoon to measure broth.

1 cup broth = 48 teaspoons

1/4 cup broth = 48 × \frac{1}{4} = 12 teaspoons

Tabitha should use 12 teaspoons of broth.

7 0
1 year ago
Which equation combines with the given equation to form a system of equations with the solution x = 3 and y = 9? x + 2y = 21
max2010maxim [7]
Yes. x=3 and y =9 are the solutions.
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3+2* 9 =21
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6 0
2 years ago
Read 2 more answers
Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. Scores o
otez555 [7]

Answer:

Due to the higher z-score, David has the higher standardized score

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Which student has the higher standardized score

Whoever had the higher z-score.

David:

Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. So X = 52, \mu = 70, \sigma = 11

Z = \frac{X - \mu}{\sigma}

Z = \frac{52 - 70}{11}

Z = -1.64

Steven:

Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6. Steven has a score of 52 on Ms. So X = 52, \mu = 64, \sigma = 6

Z = \frac{X - \mu}{\sigma}

Z = \frac{52 - 64}{6}

Z = -2

Due to the higher z-score, David has the higher standardized score

3 0
2 years ago
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