S(p) = 400 - 4p + 0.00002p^4
D(p) = 2800 - 0.0012p^3
S(p) = D(p)
400 - 4p + 0.00002p^4 = 2800 - 0.0012p^3
0.00002p^4 + 0.0012p^3 - 4p - 2400 = 0
p = $96.24
Answer:
1 : 20 20 students for every 1 teacher
Step-by-step explanation:
divide both sides by 12
The answer is 6.4
It is positive because the 11.4 is larger than the negatvie 5.
I hope this helps!
Answer:
Yes the sample can be use to make inference
Step-by-step explanation:
The inference is possible if the conditions:
p*n > 10 and q*n > 10
where p and q are the proportion probability of success and q = 1 - p
n is sample size
Then p = 12 / 30 = 0,4 q = 1 - 0,4 q = 0,6
And p*n = 0,4 * 30 = 12 12 > 10
And q*n = 0,6 * 30 = 18 18 > 10
Therefore with that sample the conditions to approximate the binomial distribution to a Normal distribution are met
Answer:
r = -39
Step-by-step explanation:
So we are trying to solve the equation for r.
-6(2r + 8) = -10(r - 3)
Divide both sides by -2. (This will make distributing much easier.)
3(2r + 8) = 5(r - 3)
Distribute the 3 on the left side and the 5 on the right side,
6r + 24 = 5r - 15
Subtract 24 from both sides.
6r = 5r - 39
Subtract 5r from both sides.
r = -39
So now we have solve the equation.
I hope you find my answer and explanation to be helpful. Happy studying. :)
