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2 years ago

8.06

Mathematics

1 answer:

Lera25 [3.4K]2 years ago

6 0

Answer:

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Probability Problems.

Based on the study that Shane conducted we can assume a couple of things. Firstly, we can see that a vast majority of shoppers are buying products they saw advertised, so we can assume that advertising a product directly affects and contributes to the sales of that particular product.

Secondly, we can tell from the study that the number 1 method for advertising products is the Internet. Since 70% of all the interviewed shoppers are buying a product they saw on the internet.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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According to a Los Angeles Times study of more than 1 million medical dispatches from 2007 to 2012, the 911 response time for me

Reil [10]

Answer:

a) $\bar X=10.65$

$Median =\frac{10.7+10.7}{2}=10.7$

$Mode= 10.7$

b) $Range = 11.8-8.3=3.5$

$s= 0.948$

c) $IQR = Q_3 -Q_1 = 11.05-10.55=0.5$

And we can find the usual limits with:

$Lower = Q_1 -1.5 IQR = 10.55 -1.5*0.5=9.8$

$Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3$

And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.

d) The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.

And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

Step-by-step explanation:

We have the following data:

11.8 10.3 10.7 10.6 11.5 8.3 10.5 10.9 10.7 11.2

Part a

We can calculate the sample mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got: $\bar X=10.65$

For the median we need to sort the values on increasing order and we have:

8.3 10.3 10.5 10.6 10.7 10.7 10.9 11.2 11.5 11.8

Since n =10 we can calculate the median as the average between the 5th and 6th position of the dataset ordered and we got:

$Median =\frac{10.7+10.7}{2}=10.7$

The mode would be the most repeated value on this case:

$Mode= 10.7$

Part b

The range is defined as $Range =Max-Min$ and if we replace we got:

$Range = 11.8-8.3=3.5$

We can calculate the standard deviation with the following formula:

$s= sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And if we replace we got:

$s= 0.948$

Part c

For this case we can use the IQR method in order to determine if 8.3 is an outlier or not.

We can calculate the first quartile with these values: 8.3 10.3 10.5 10.6 10.7 10.7 and $Q_1= \frac{10.6+10.7}{2}=10.55$

And for the Q3 we can use: 10.7 10.7 10.9 11.2 11.5 11.8 and we got $Q_3 = \frac{10.9+11.2}{2}=11.05$

Then we can find the IQR like this:

$IQR = Q_3 -Q_1 = 11.05-10.55=0.5$

And we can find the usual limits with:

$Lower = Q_1 -1.5 IQR = 10.55 -1.5*0.5=9.8$

$Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3$

And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.

Part d

The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.

And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

6 0

2 years ago

What are the solution(s) to the quadratic equation 50 – x2 = 0? x = ±2Plus or minus 2 StartRoot 5 EndRoot x = ±6Plus or minus 6

Serga [27]

Question:

What are the solution(s) to the quadratic equation 50 – x2 = 0?

A) x = ±2Plus or minus 2 StartRoot 5 EndRoot

B) x = ±6Plus or minus 6 StartRoot 3 EndRoot

C) x = ±5Plus or minus 5 StartRoot 2 EndRoot

D) no real solution

Answer:

C) x = ±5Plus or minus 5 StartRoot 2 EndRoot

3 0

2 years ago

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Determine the density in g/cm3 of a mineral that has a volume of 3.8 cm3 and a mass of 22.4 g.

kherson [118]

Answer:

5.89 g/cm³

Step-by-step explanation:

givens,

Mass = 22.4 g

volume = 3.8 cm³

Density = mass / volume

= 22.4 / 3.8

= 5.89 g/cm³

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2 years ago

the backpacking club is having some posters printed the printer charges $180 plus $250 per poster how many posters can be printe

svet-max [94.6K]

They would be able to print 3 posters

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2 years ago

A customer at Logan’s Plants pays $20.00 for a bush and $11.50 per pack of flowers. The table shows the total cost to purchase o

Volgvan

Answer:

<h2>brainiest me</h2>

Step-by-step explanation:

how many expensive packs of flower is 3,150$

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2 years ago