Answer:
The variance in weight is statistically the same among Javier's and Linda's rats
The null hypothesis will be accepted because the P-value (0.53 ) > ∝ ( level of significance )
Step-by-step explanation:
considering the null hypothesis that there is no difference between the weights of the rats, we will test the weight gain of the rats at 10% significance level with the use of Ti-83 calculator
The results from the One- way ANOVA ( Numerator )
with the use of Ti-83 calculator
F = .66853
p = .53054
Factor
df = 2 ( degree of freedom )
SS = 23.212
MS = 11.606
Results from One-way Anova ( denominator )
Ms = 11.606
Error
df = 12 ( degree of freedom )
SS = 208.324
MS = 17.3603
Sxp = 4.16657
where : test statistic = 0.6685
p-value = 0.53
level of significance ( ∝ ) = 0.10
The null hypothesis will be accepted because the P-value (0.53 ) > ∝
where Null hypothesis H0 = ∪1 = ∪2 = ∪3
hence The variance in weight is statistically the same among Javier's and Linda's rats
Answer:
1. 2x - 5 + x = 20
Step-by-step explanation:
Let Aseem's car as x,
Stana's = 5 less than 2x
= 2x - 5
Aseem's + Stana's = 20
x + 2x - 5 = 20
2x - 5 + x = 20
Scale factor is:
factor = (new length) / (old length)
Ivan correctly inserted numbers and correctly divided these two numbers by 5.
There is no error in the shown picture.
Answer:
t(5,000,000,000) = 7.5 sec
Explanation:
A computer take 0.0000000015 sec to do a calculation.
Given a function t(n) = 0.0000000015n
where n represent the number of calculation.
We need to find the total time computer to do 5 billion calculations.
We plug n = 5 billion = 5,000,000,000
Total taken time t(n) =0.0000000015n
t(5,000,000,000) = (0.0000000015)*(5,000,000,000)
t(5,000,000,000) = 1.5*5
t(5,000,000,000) = 7.5 sec
That's the final answer.
I hope it will help you.
Answer: The lowest value: 100 and highest value: - 150 .
If we were to build the box plot for this data, the box would stretch between 
and 
.
Step-by-step explanation:
We know that the box-plot is the graphical way to represent the five -number summary (Minimum value , First quartile 
, Median , Third Quartile 
, Maximum value).
Where , the box streches between the first quartile and the third quartile .
Given : The cost of taking your pet aboard the air flight with you in the continental US varies according to the airlines.
The five number summary for prices based on a sample of major US airlines was:
Min = 60,
Median = 110
Max = 150
If we were to build the box plot for this data, the box would stretch between and .
Hence, the lowest value: 100 and highest value: 125 .
