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Rom4ik [11]
2 years ago
9

Suppose that a survey was taken of 32 people and each person was asked if they approved or disapproved of the president's action

s during the government shutdown. Nineteen people said that they approved. Which of the following statements correctly describes how the confidence interval for the population proportion of people that approved the President's actions during the government shutdown? Group of answer choices There are not 15 observed successes and 15 observed failures. A confidence interval can not be done. There are not 15 observed successes and 15 observed failures. A confidence interval can be computed by adding 2 successes and 2 failures. There are not 15 observed successes and 15 observed failures. A confidence interval can be computed by adding 4 successes and 5 failures. There are at least 15 observed successes and 15 observed failures. A large sample confidence interval for the population proportion can be computed (phat +/- z * sqrt(p*(1-p)/n) with no additional values added.
Mathematics
1 answer:
erastova [34]2 years ago
5 0

Answer:

Option c

Step-by-step explanation:

--The large-sample confidence interval

formula for proportions is valid if np ≥ 15 and n(1-p) ≥ 15. The large sample confidence

interval only contain the true value a certain percentage of the time. A 95% CI will contain the

value 95% of the time. You add 2 successes and 2 failures.

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According to a "how to stop bullying" Web site, 15% of students report experiencing bullying one to three times within the most
AlekseyPX

Answer:

His 95% confidence interval is (0.065, 0.155).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

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95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 - 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.065

The upper limit of this interval is:

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His 95% confidence interval is (0.065, 0.155).

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1 year ago
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