Answer: 0.31
Step-by-step explanation:
Let A denotes the event of Tampa Bay Buccaneers will score a touchdown on their opening drive and B denote the event that their defense will have 3 or more sacks in the game.
Given : P(A)=0.14 P(B) = 0.31 P(A or B)=0.14
Formula : P(A and B)= P(A) + P(B) - P(A or B)
Now, the probability that they will both score a touchdown on the opening drive and have 3 or more sacks in the game will be :-
P(A and B)= 0.14 + 0.31 - 0.14=0.31
Hence, the required probability : 0.31
Answer:gui
Step-by-step explanation:
Answer:
N + D = 175
.05N + .10D = $13.30
Step-by-step explanation:
You need a system of equations to get the correct answer that applies to both constraints.
Answer:
G = (9.4, 9,4)
Step-by-step explanation:
The ratio is applied in the x-distance and the y-distance. The ratio is 2:3 so you have to divide the distances by 5 and 2/5 correspond to FG and 3/5 to GH
x-distance:
x2 - x1 = 16 - 5 = 11
11/5 = 2.2
y-distance:
y2 - y1 = 13 - 7 = 6
6/5 = 1.2
Point G = Point F + (2.2*2, 1.2*2)
Point G = (5, 7) + (4.4, 2.4)
= (9.4, 9.4)
Answer:
A. 1 in. = 22.5 mi
Step-by-step explanation:
Since 22.5 x 10 = 225, we can conclude that this will fit the scale needed. B. is incorrect because it is simply illogical in context with a scale and the question. C. is incorrect since 10 x 0.04 is 0.4, which does not equal 10. D. is incorrect since we need the scale to add up to equal 225 mi, not 22.5.
Hope this helps!
