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Ivahew [28]
1 year ago
15

Which expressions are equivalent to -6n+(-12)+4n

Mathematics
1 answer:
GaryK [48]1 year ago
5 0

Answer:

-2n - 12

Step-by-step explanation:

Combine like terms. Note that each term has one variable (n). Also note  that one negative sign and one positive sign results in a negative sign.

-6n + (-12) + 4n = -6n  + 4n - 12 = -2n - 12

-2n - 12 is your answer

~

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This question is Incomplete

Complete Question

Recall the hurricane relief fund context from the previous investigation. Bob set up a hurricane relief donation fund and started it off by donating $ 35 . Instead of tripling in value each day, suppose it doubled in value each day

Complete the following table showing the account values at the end of each day.

Number of days since the initial investment, n Amount (in dollars) in the relief account, A

0 1 2 3 4

Answer:

Number of days(n) = Amount (in dollars) in the relief account(A)

0 = $35

1 = $70

2 = $140

3 = $280

4 = $560

Step-by-step explanation:

The formula for doubling time

P(t) = Po(2)^t/k

Where P = Amount after time t

Po = Initial Amount

t = number of days

k = Frequency at which it doubles

For 0 days

t = 0, k = 1, P(o) = $35

P(t) = Po(2)^t/k

P(0) = $35(2)^0/1

= $35(2)⁰

= $35 × 1

= $35

For 1 day

t = 1, k = 1 , P(0) = $35

P(t) = Po(2)^t/k

P(0) = $35(2)^1/1

= $35(2)¹

= $35 × 2

= $70

For 2 days

P(t) = Po(2)^t/k

t = 2, k = 1, P(0) = $35

P(0) = $35(2)^2/1

= $35(2)²

= $35 × 4

= $140

For 3 days

P(t) = Po(2)^t/k

t = 3, k = 1

P(0) = $35(2)^3/1

= $35(2)³

= $35 × 8

= $280

For 4 days

P(t) = Po(2)^t/k

t = 3, k = 1, P(0) = $35

P(0) = $35(2)^5/1

= $35(2)⁴

= $35 × 16

= $560

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2 years ago
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I think the answer would be 56. Bc the first job has 8 different people who could get the job and then once someone is chosen for that slot the next teaching position only has 7 candidates. So you would take 8*7 which equals 56.

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Why can you use cross products to solve the proportion StartFraction 18 over 5 EndFraction = StartFraction x over 100 EndFractio
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Answer:

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