Solve x2 + 12x = –11 by completing the square. Which is the solution set of the equation? {–11, –1} {–11, 1} {11, –1} {11, 1} ,
2 answers:
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Answer:
Suppose you want to assess student attitudes about the new campus center by surveying 100 students at your school. In this example, the group of 100 students represents the Sample, and all of the students at your school represent the Population.
Step-by-step explanation:
Previous concepts
The term sample represent a set of observations or individuals selected from a population. And we can have a random sample (when all the individuals have the same probability of being selected) or a non random sample (when not all the individuals have probability of inclusion into the sample)
The term population represent the total of observations or individuals with a common characteristic.
If N represent the sample of the population and n the sample size we have always this inequality:
Solution to the problem
Suppose you want to assess student attitudes about the new campus center by surveying 100 students at your school. In this example, the group of 100 students represents the Sample, and all of the students at your school represent the Population.
Answer: a. A point estimate for p is 0.597 .
b. The 95% confidence interval for p.
Lower limit = 0.48
Upper limit = 0.71
Step-by-step explanation:
Given : Sample size of professional actors : n= 67
Number of extroverts : x= 40
Let p represent the proportion of all actors who are extroverts.
a. The point estimate for p = sample proportion =
b. Confidence interval for population proportion :
Since the critical value for 95% confidence interval is 1.96 , so the 95% confidence interval for p would be
In the 95% confidence interval for p.
Lower limit = 0.48
Upper limit = 0.71
Answer:
Step-by-step explanation:
The position function is
and if we are looking for the time(s) that the ball is 10 feet above the surface of the moon, we sub in a 10 for s(t) and solve for t:
and
and factor that however you are currently factoring quadratics in class to get
t = .07 sec and t = 18.45 sec
There are 2 times that the ball passes 10 feet above the surface of the moon, once going up (.07 sec) and then again coming down (18.45 sec).
For part B, we are looking for the time that the ball lands on the surface of the moon. Set the height equal to 0 because the height of something ON the ground is 0:
and factor that to get
t = -.129 sec and t = 18.65 sec
Since time can NEVER be negative, we know that it takes 18.65 seconds after launch for the ball to land on the surface of the moon.