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1 year ago

If ED = 5y + 6 and DB = y + 30, find the value of y. Then find ED, DB, and EB.

Mathematics

1 answer:

Gemiola [76]1 year ago

3 0

Answer:

Part 1) The value of y=6

Part 2) ED=36, DB=36 and EB=72

Step-by-step explanation:

In this problem we know that

ED=DB -----> equation A

EB=ED+DB -----> equation B

The point D is the midpoint ED

see the attached figure to better understand the problem

step 1

Find the value of y

Substitute the given values in the equation A

$5y+6=y+30$

solve for y

$5y-y=30-6$

$4y=24$

$y=6$

step 2

Find the value of ED,DB and EB

$ED=5y+6$

substitute the value of y

$ED=5(6)+6=36$

Remember that

ED=DB

therefore

$DB=36$

Find the value of EB

EB=ED+DB

$EB=36+36=72$

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Given directed line segment QS , find the coordinates of R

Degger [83]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete, what are the coordinates of point Q and R. But I would show how to solve this.

The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at ( $x_1,y_1$ ) and B( $x_2,y_2$ ) is given by the formula:

$x=\frac{a}{a+b}(x_2-x_1)+x_1\\ \\y=\frac{a}{a+b}(y_2-y_1)+y_1$

If point Q is at ( $x_1,y_1$ ) and S at ( $x_2,y_2$ ) and R(x, y) divides QS in the ratio QR to RS is 3:5, The coordinates of R is:

$x=\frac{3}{3+5}(x_2-x_1)+x_1=\frac{3}{8}(x_2-x_1)+x_1\\ \\y=\frac{3}{3+5}(y_2-y_1)+y_1=\frac{3}{8}(y_2-y_1)+y_1$

Let us assume Q(−9,4) and S(7,−4)

$x=\frac{3}{8}(7-(-9))+(-9)=\frac{3}{8}(16)-9=-3\\\\y=\frac{3}{8}(-4-4)+4=\frac{3}{8}(-8)+4=1$

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2 years ago

Solve for x*<br> (17x - 8)

djyliett [7]

Answer:x=4

Step-by-step explanation:

This triangle is an equilateral triangle with all angles equal.

Sum of angles in a triangle=180

17x-8+17x-8+17x-8=180

Collect like terms

17x+17x+17x-8-8-8=180

51x-24=180

51x=180+24

51x=204

Divide both sides by 51

51x/51=204/51

x=4

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1 year ago

A study was conducted to determine the mean birth weight of a certain breed of kittens. Consider the birth weights of kittens to

kipiarov [429]

3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.

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1 year ago

Let XXX and YYY be the following sets: X = \{9, 25\}X={9,25}X, equals, left brace, 9, comma, 25, right brace Y = \{1, 4, 9,16,25

Dmitry_Shevchenko [17]

Answer:

The answer is " $\bold{ \{\phi\}}$ "

Step-by-step explanation:

Given value:

$\ Set\ X = \{9, 25\} \\\\\ Set \ Y = \{ 1,4,9,16,25 \}\\\\Find: \\\\Set (X- Y) \\\\$

When we subtract set X - Y it means, that it will give only, that value which is not available on the set Y.

$\{X-Y\} = \{\phi\}$

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2 years ago

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Which graph represents the function f(x)=x4+4x3−12x2−32x+64?

sp2606 [1]

$f(x)=x^4+4x^3-12x^2-32x+64$

The degree of f(x) is 4. Also the leading coefficient is 1 and it is positive

So as x approaches infinity then y approaches infinity

as x approaches -infinity then y approaches infinity

The first and fourth graph goes up and it satisfies the above . so we ignore the second and third graph.

Now we check the x intercepts of the first graph

x intercepts of first graph is -4 and 2

Plug in -4 for x in f(x) and check whether we get 0

$f(x)=x^4+4x^3-12x^2-32x+64$

$f(x)=(-4)^4+4(-4)^3-12(-4)^2-32(-4)+64=0$

Now plug in 2 for x and check

$f(x)=(2)^4+4(2)^3-12(2)^2-32(2)+64=0$

So -4 and 2 are the x intercepts that satisfies f(x)

Hence first option is the graph of $f(x)=x^4+4x^3-12x^2-32x+64$

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1 year ago

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