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2 years ago

If ED = 5y + 6 and DB = y + 30, find the value of y. Then find ED, DB, and EB.

Mathematics

1 answer:

Gemiola [76]2 years ago

3 0

Answer:

Part 1) The value of y=6

Part 2) ED=36, DB=36 and EB=72

Step-by-step explanation:

In this problem we know that

ED=DB -----> equation A

EB=ED+DB -----> equation B

The point D is the midpoint ED

see the attached figure to better understand the problem

step 1

Find the value of y

Substitute the given values in the equation A

$5y+6=y+30$

solve for y

$5y-y=30-6$

$4y=24$

$y=6$

step 2

Find the value of ED,DB and EB

$ED=5y+6$

substitute the value of y

$ED=5(6)+6=36$

Remember that

ED=DB

therefore

$DB=36$

Find the value of EB

EB=ED+DB

$EB=36+36=72$

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2 years ago

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Money Spent on Road Repair A politician wishes to compare the variances of the amount of money spent for road repair in two diff

Mkey [24]

Answer:

(A) Null Hypothesis, $H_0$ : $\sigma_1^{2} =\sigma_2^{2}$ {means that there is no significant difference in the variances of the amounts spent in the two counties}

Alternate Hypothesis, $H_A$ : $\sigma_1^{2} \neq \sigma_2^{2}$ {means that there is a significant difference in the variances of the amounts spent in the two counties}

(B) The F-table gives critical values of 0.359 and 2.781 for (14,17) degrees of freedom for the two-tailed test.

(C) The value of the F-test statistic is 0.611.

(D) We conclude that there is no significant difference in the variances of the amounts spent in the two counties.

Step-by-step explanation:

We are given that a politician wishes to compare the variances of the amount of money spent on road repair in two different counties.

The data are given here below;

County A County B

s1 = $11,596 s2 = $14,837

n1 = 15 n2 = 18

Let $\sigma_1^{2}$ = variances of the amounts spent in County A.

$\sigma_2^{2}$ = variances of the amounts spent in County B.

(A) So, Null Hypothesis, $H_0$ : $\sigma_1^{2} =\sigma_2^{2}$ {means that there is no significant difference in the variances of the amounts spent in the two counties}

Alternate Hypothesis, $H_A$ : $\sigma_1^{2} \neq \sigma_2^{2}$ {means that there is a significant difference in the variances of the amounts spent in the two counties}

The test statistics that would be used here Two-sample F-test statistics distribution;

T.S. = $\frac{s_1^{2} }{s_2^{2} } \times \frac{\sigma_2^{2} }{\sigma_1^{2} }$ ~ $F__n_1_-_1,_ n_2_-_1$

where, $s_1$ = sample standard deviation for County A = $11,596

$s_2$ = sample standard deviation for County B = $14,837

$n_1$ = sample size for County A = 15

$n_2$ = sample size for County B = 18

(B) Now at 0.05 level of significance, the F-table gives critical values of 0.359 and 2.781 for (14,17) degrees of freedom for the two-tailed test.

(C) So, the test statistics = $\frac{11,596^{2} }{14,837^{2} } \times 1$ ~ $F__1_4,_ 1_7$

= 0.611

The value of the F-test statistic is 0.611.

Now, as we can see that our test statistics lie within the range of critical values of F, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

(D) Therefore, we conclude that there is no significant difference in the variances of the amounts spent in the two counties.

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2 years ago

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Step-by-step explanation:

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The question is incomplete:

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-Find the dealer's percent of the base price.

-Find the dealer's percent of the options price.

-What is the estimated dealer's cost?

Answer:

-What is the sticker price of the vehicle? $31,342

-Find the dealer's percent of the base price: $20,484

-Find the dealer's percent of the options price: $7,094

-What is the estimated dealer's cost? $28,348

Step-by-step explanation:

-The sticker price is the result of adding the base price plus the options plus the destination charge.

Sticker price= base price + options + destination charge

Sticker price= $22,510+$8,062+$770

Sticker price= $31,342

-Dealer's percent of the base price: It is 91% of the base price:

$22,510*91%= $20,484

-Dealer's percent of the options price: It is 88% of the options:

$8,062*88%= $7,094

-Estimated dealer's cost= Percent of base price+percent of options price+destination charge

Estimated dealer's cost= $20,484+$7,094+$770

Estimated dealer's cost=$28,348

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