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marshall27 [118]
2 years ago
8

1. Assume the reserve requirement is 10%. First National Bank receives a deposit of $5,400. If there is no slippage, how much co

uld the money supply expand? Explain and show your work.
Mathematics
1 answer:
Andru [333]2 years ago
3 0
Compose the result function for 400 by replacing the function designators with the actual functions 400 
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Miguel wrote the predicted and residual values for a data set using the line of best fit y = 1.82x – 4.3. He left out two of the
Dmitry_Shevchenko [17]

Answer:

c

Step-by-step explanation:

i think it was c

5 0
1 year ago
Read 2 more answers
The length of the day in Lagos, Nigeria (in minutes), ttt days since the beginning of the year can be estimated by this formula:
Ronch [10]

Answer:

The longest day of the year is day 172  

Step-by-step explanation:

Since the length of day is L(t)=727+22sin[2π(t−80.75)/365], the maximum length of day is obtained when sin[2π(t−80.75)/365] is at its maximum value which is 1. So. sin[2π(t−80.75)/365] = 1

We now solve this to find the day at which this maximum value occurs.

sin[2π(t−80.75)/365] = 1

[2π(t−80.75)/365] = sin⁻¹(1)

[2π(t−80.75)/365] = π/2

dividing both sides by 2π/365, we have

[2π(t−80.75)/365] ÷ 2π/365 = π/2 ÷ 2π/365

t−80.75 = 365/4

t−80.75 = 91.25

t = 91.25 + 80.75

t = 172

The longest day of the year is day 172

6 0
1 year ago
A grapefruit has a peel that is 1cm thick and a total diameter of 12cm. What percentage of volume of the grapefruit is the peel?
ira [324]

Answer:

0.3056 or 30.56%

Step-by-step explanation:

The volume of the grapefruit with the peel is:

V_p=\frac{4 \pi (d/2)^2}{3}\\V_p=\frac{4 \pi (12/2)^2}{3}\\V_p=48 \pi

When removing the peel, the grapefruit diameter becomes 10 cm (take out 1 cm of peel from each side). The volume of the grapefruit without the peel is:

V_n=\frac{4 \pi (d/2)^2}{3}\\V_n=\frac{4 \pi (10/2)^2}{3}\\V_n=33.333 \pi

The percentage of the volume correspondent to the peel is given by the difference between both volumes, divided by the total volume:

\%P = \frac{48\pi - 33.333\pi}{48\pi}\\ \%P =0.3056 = 30.56\%

30.56% of volume of the grapefruit is the peel.

4 0
2 years ago
At a local pizza parlor , game tickets can be traded for small toys . The rate is 10 tickets for 4 small toys . If meg won 55 ti
tangare [24]

Meg can trade her tickets in for 20 small toys.

6 0
2 years ago
Owen has enough materials to build up to 10 birdhouses in shop class. Each birdhouse needs 12 square feet of wood. The function
kirill [66]

Answer:

  D.  D: 0 ≤ b ≤ 10; R: 0 ≤ W(b) ≤ 120

Step-by-step explanation:

The problem statement tells you Owen can build up to 10 birdhouses, and that b represents that number. Then 0 ≤ b ≤ 10 is the domain described by the problem statement.

It also tells you that W(b) = 12b, so filling in values from 0 to 10 gives a range from 0 to 120: 0 ≤ W(b) ≤ 120.

These observations match choice D.

8 0
1 year ago
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