Answer:
The equations are:
and
Step-by-step explanation:
Given
Represent bones eaten Today with T and yesterday with Y
Required
Write the equation
In the first statement, we have that:
Reading further; In the second statement
Hence, the equations are:
and
Solving further:
Substitute 2Y for T in the second equation
Divide both sides by 4
Recall that
Let us assume uniform width = x cm wide.
Length of rectangular portrait = 50cm and width of rectangular portrait = 70cm.
Therefore, length of rectangle made by frame = 50 + x+x = (2x+50) cm.
And width of rectangle made by frame = 70+x+x = (2x+70) cm.
We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.
Total area of the rectangle made by frame would be = (2x+50) * (2x+70)
We know,
Actual area of frame = Area of rectangle made by frame - area of rectangular portrait.
We also given "the area of the frame is the same as the area of the portrait."
We can setup an equation now,
3500 = (2x+50) * (2x+70) - 3500.
Subtracting 3500 from both sides, we get
3500-3500 = (2x+50) * (2x+70) - 3500-3500.
0 = (2x+50) * (2x+70) -7000.
FOIL (2x+50) * (2x+70), we get
0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.
0 = 4x^2 +140x +100x +3500 -7000.
4x^2 +240x -3500 = 0.
Dividing whole equation by 4, we get
x^2 +60x - 875 =0
Applying quadratic formula , we get
We cant take negative value.
So,
We could take approximately 12 cm.
Answer:
<u>Properties that are present are </u>
Property I
Property IV
Step-by-step explanation:
The function given is where b > 1
Let's take a function, for example,
Let's check the conditions:
I. As the x-values increase, the y-values increase.
Let's put some values:
y = 2 ^ 1
y = 2
and
y = 2 ^ 2
y = 4
So this is TRUE.
II. The point (1,0) exists in the table.
Let's put 1 into x and see if it gives us 0
y = 2 ^ 1
y = 2
So this is FALSE.
III. As the x-value increase, the y-value decrease.
We have already seen that as x increase, y also increase in part I.
So this is FALSE.
IV. as the x value decrease the y values decrease approaching a singular value.
THe exponential function of this form NEVER goes to 0 and is NEVER negative. So as x decreases, y also decrease and approached a value (that is 0) but never becomes 0.
This is TRUE.
Option I and Option IV are true.