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atroni [7]
2 years ago
5

I have 28 cubes. How many tens and ones can I make? -----tens ----ones ten------ ones

Mathematics
2 answers:
asambeis [7]2 years ago
3 0
You can make 2 tens and 8 ones
Alex_Xolod [135]2 years ago
3 0
2 tens 2x10=20
8 ones
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A psychologist would like to examine the effects of different testing methods on the final performance of college students. One
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Answer:

Check the explanation

Step-by-step explanation:

One way ANOVA

The null and alternative hypothesis for this one way ANOVA is given as below:

Null hypothesis: H0: There is no significant difference in the averages of the scores for the quizzes, exams and final only.

Alternative hypothesis: There is a significance difference in the averages of the scores for the quizzes, exams and final only.

The ANOVA table with calculations can be seen in the attached images below:

In the attached image below, we get the p-value for this one way ANOVA test as 0.0221. We do not reject the null hypothesis if the p-value is greater than the given level of significance and we reject the null hypothesis if the p-value is less than the given level of significance or alpha value.

In the attached image below, we are given that the p-value = 0.0221 and level of significance or alpha value = 0.05, that is p-value is less than the given level of significance. So, we reject the null hypothesis that there is no significant difference in the averages of the scores for the quizzes, exams and final only. This means we conclude that there is a significance difference in the averages of the scores for the quizzes, exams and final only.

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Estimated quotient of 119÷23​
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Answer:

5...................

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Bailey likes the shape of her friend's pool, but she wants one that is half the volume. According to Cavalieri’s Principle, what
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Step-by-step explanation: I need this in order to figure out the problem and give you a helpful answer.

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Kennedy served 15 3 / 4 hours of volunteer service last month. She served 21 5 / 6 hours of volunteer service this month. How ma
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. Solve the following initial value problem: (t2−20t+51)dydt=y (t2−20t+51)dydt=y with y(10)=1y(10)=1. (Find yy as a function of
Semenov [28]

Answer:

y=(\frac{t-17}{t-3})^{\frac{1}{14}}

Step-by-step explanation:

We are given that initial value problem

t^2-20t+51)\frac{dy}{dt}=y

\frac{dy}{y}=\frac{dt}{t^2-20t+51}

\frac{dy}{y}=\frac{dt}{t^2-3t-17t+51}

\frac{dy}{y}=\frac{dt}{(t(t-3)-17(t-3)}

\frac{dy}{y}=\frac{dt}{(t-3)(t-17)}

\frac{1}{(t-3)(t-17)}=\frac{A}{t-3}+\frac{B}{t-17}

\frac{1}{(t-3)(t-17)}=\frac{A(t-17)+B(t-3)}{(t-3)(t-17)}

1=A(t-17)+B(t-3)...(1)

Substitute t-3=0

t=3

t-17=0

t=17

Substitute t=3 in equation (1)

1=A(3-17)+0

1=-14A

A=-\frac{1}{14}

Substitute t=17

1=B(17-3)

1=14B

B=\frac{1}{14}

Substitute the values of A and B

\frac{1}{(t-3)(t-17)}=-\frac{1}{14}(\frac{1}{t-3})+\frac{1}{14}(\frac{1}{t-17})

\int\frac{dy}{y}=-\frac{1}{14}\int\frac{dt}{t-3}+\frac{1}{14}\int\frac{dt}{t-17}

ln y=-\frac{1}{14}ln\mid{t-3}\mid+\frac{1}{14}\mid{t-17}\mid+ln C

By using formula:\frac{dx}{x}=ln x+C

ln y=\frac{1}{14}(-ln\mid{t-3}\mid+ln\mid{t-17}\mid)+ln C

Using formula:ln x-ln y=ln \frac{x}{y}

ln y=\frac{1}{14}(ln\mid{\frac{t-17}{t-3}}\mid)+ln C

ln y=\frac{1}{14}ln\mid{\frac{t-17}{t-3}}\mid+ ln C

Substitute y(10)=1

ln 1=\frac{1}{14}ln\mid\frac{10-17}{10-3}\mid+ln C

0=0+ln C

Because ln 1=0

lnC=0

C=e^0=1

Because ln x=y\implies x=e^y

Substitute the value of C

ln y=\frac{1}{14}ln\mid\frac{t-17}{t-3}\mid+ln1

ln y=\frac{1}{14}ln\mid\frac{t-17}{t-3}\mid+0

ln y=\frac{1}{14}ln\mid\frac{t-17}{t-3}\mid

14ln y=ln\mid\frac{t-17}{t-3}\mid

lny^{14}=ln\mid\frac{t-17}{t-3}\mid

By using identity blog a= loga^b

y^{14}=\frac{t-17}{t-3}

y=(\frac{t-17}{t-3})^{\frac{1}{14}}

6 0
2 years ago
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