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Setler [38]
2 years ago
15

In a large city, 46% of adults support the local football team building a new stadium. If a poll is taken from a random sample o

f 80 adults in the large city, which of the following properly describes the sampling distribution of the sample proportion of adults who support the stadium?*
Mathematics
1 answer:
Sveta_85 [38]2 years ago
7 0

Answer: 0.46, 0.056, the distribution is approximately normal

Step-by-step explanation: The shape is approximately normal since the expected number of successes equals 36.8 and the expected number of failures equals 43.2 are both larger than 10

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Find the quantity q that maximizes profit if the total revenue, R(q), and total cost, C(q) are given in dollars by R(q)=3q−0.002
marysya [2.9K]

Answer:

The value of q that maximize the profit is q=200 units

Step-by-step explanation:

we know that

The profit is equal to the revenue minus the cost

we have

R(q)=3q-0.002q^{2} ---> the revenue

C(q)=200+2.2q ---> the cost

The profit  P(q) is equal to

P(q)=R(q)-C(q)

substitute the given values

P(q)=(3q-0.002q^{2})-(200+2.2q)

P(q)=3q-0.002q^{2}-200-2.2q

P(q)=-0.002q^{2}+0.8q-200

This is a vertical parabola open downward (because the leading coefficient is negative)

The vertex represent a maximum

The x-coordinate of the vertex represent the value of q that maximize the profit

The y-coordinate of the vertex represent the maximum profit

using a graphing tool

Graph the quadratic equation

The vertex is the point (200,-120)

see the attached figure

therefore

The value of q that maximize the profit is q=200 units

6 0
2 years ago
The amount of time a passenger waits at an airport check-in counter is random variable with mean 10 minutes and standard deviati
Stolb23 [73]

Answer:

(a) less than 10 minutes

= 0.5

(b) between 5 and 10 minutes

= 0.5

Step-by-step explanation:

We solve the above question using z score formula. We given a random number of samples, z score formula :

z-score is z = (x-μ)/ Standard error where

x is the raw score

μ is the population mean

Standard error : σ/√n

σ is the population standard deviation

n = number of samples

(a) less than 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Therefore, the probability that the average waiting time waiting in line for this sample is less than 10 minutes = 0.5

(b) between 5 and 10 minutes

i) For 5 minutes

x = 5 μ = 10, σ = 2 n = 50

z = 5 - 10/2/√50

z = -5 / 0.2828427125

= -17.67767

P-value from Z-Table:

P(x<5) = 0

Using the z table to find the probability

P(z ≤ 0) = P(z = -17.67767) = P(x = 5)

= 0

ii) For 10 minutes

x = 10 μ = 10, σ = 2 n = 50

z = 10 - 10/2/√50

z = 0 / 0.2828427125

z = 0

Using the z table to find the probability

P(z ≤ 0) = P(z < 0) = P(x = 10)

= 0.5

Hence, the probability that the average waiting time waiting in line for this sample is between 5 and 10 minutes is

P(x = 10) - P(x = 5)

= 0.5 - 0

= 0.5

3 0
2 years ago
600 can be written as 2a x b x cd where a,b,c and d are all prime numbers find the values of a, b, c and d
mihalych1998 [28]
The prime factorisation of 600 is given by

600 = 2 \times 2 \times 2 \times 3 \times 5 \times 5 = 2^3 \times 3 \times 5^2

Therefore, a = 3, b = 3, c = 5 and d = 2.
4 0
2 years ago
The percent defective for parts produced by a manufacturing process is targeted at 4%. The process is monitored daily by taking
Anna [14]

Answer:

The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 160, \pi = \frac{14}{160} = 0.088

88% confidence level

So \alpha = 0.12, z is the value of Z that has a pvalue of 1 - \frac{0.12}{2} = 0.94, so Z = 1.555.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.088 - 1.555\sqrt{\frac{0.088*0.912}{160}} = 0.053

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.088 + 1.555\sqrt{\frac{0.088*0.912}{160}} = 0.123

The 88% confidence interval for the proportion of defectives today is (0.053, 0.123)

6 0
2 years ago
For the given functions f (x), let x0 = 0, x1 = 0.6, and x2 = 0.9. construct interpolation polynomials of degree at most one and
barxatty [35]
Check the attached file for the solution.

6 0
2 years ago
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