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Gre4nikov [31]
2 years ago
14

For what values of m does the graph of y = 3x^2 + 7x + m have two x-intercepts? a) m>12/49 b) m<12/49 c) m<49/12 d) m&g

t; 49/12
Mathematics
1 answer:
den301095 [7]2 years ago
6 0

The quadratic formula, has a part we call the "discriminant" defined by the variables that are inside the square root, and is denotated by "delta":

<span>Δ=<span>b2</span>−4ac</span> Whenever we solve a quadratic equation that is complete and we analyze the discriminant, we can get 3 scenarios: <span>if→Δ>0<span>=></span>∃<span>x1</span>,<span>x2</span>/a<span>x2</span>+bx+c=0</span> This just means: "if the discriminant is greater than zero, there will exist two x-intercepts" And for the second scenario: <span>if→Δ=0→∃<span>xo</span>/a<span>x2</span>+bx+c=0</span> This means: "if the discriminant is equal to zero, there will be one and only one x-intercept" And for the last scenario: <span>if→Δ<0→∃x∉R/a<span>x2</span>+bx+c=0</span> This means that :"if the discriminant is less than zero, there will be no x-intercepts" So, if we take your excercise and analyze the the discriminant: <span>3<span>x2</span>+7x+m=y</span> we will find the values that satisfy y=0 : <span>3<span>x2</span>+7x+m=0</span> And we'll analyze the discriminant: <span>Δ=<span>72</span>−4(3)(m)</span> And we are only interested in the values that make the discriminant equal zero: <span><span>72</span>−4(3)(m)=0</span> All you have to do is solve for "m".

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A square based brass plate in 4mm high and has a mass of 1.05kg. The density of the brass is 4.2g/cm3, calculate the length of t
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Answer:

Length = 25cm

Step-by-step explanation:

Given

Brass Shape: Square

Density = 4.2g/cm^3

Mass = 1.05kg

Height = 4mm

Required

Determine the length of the plate

First, we need to calculate the Volume of the Brass using

Density = \frac{Mass}{Volume}

Make Volume the subject of formula

Volume = \frac{Mass}{Density}

Substitute 1.05kg for Mass and 4.2g/cm³ for Density

Volume = \frac{1,05\ kg}{4.2\ g/cm^3}

Convert 1.05 kg to grams

Volume = \frac{1.05 * 1000\ kg}{4.2\ g/cm^3}

Volume = \frac{1050 \ kg}{4.2\ g/cm^3}

Volume = \frac{1050 \ kg}{4.2\ g/cm^3}

Volume = 250cm^3

Next is to determine the Area of the brass;

Volume = Height * Area

Substitute 250cm³ for Volume and 4mm for Height

250cm^3 = 4mm * Area

Convert mm to cm

250cm^3 = 4 * 0.1cm * Area

250cm^3 = 0.4cm * Area

Divide both sides by 0.4cm

\frac{250cm^3}{0.4cm} = \frac{0.4cm * Area}{0.4cm}

\frac{250cm^3}{0.4cm} =Area

625cm^2 = Area

Area = 625cm^2

Lastly, we'll calculate the length of the brass

Since the brass is square based;

Area = Length^2

Substitute 625cm² for Area

625cm^2 = Length^2

Take square root of both sides

\sqrt{625cm^2} = Length

25cm = Length

Length = 25cm

<em>Hence, the length of the square brass is 25cm</em>

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