What is being requested, if I'm not mistaken, is the number of permutations for placing each of the 8 beads on the vertices of the cubes;
In this case, we have 8 different beads and 8 possible locations for each of them;
So the number of permutations is:
8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40320
I'm pretty sure it is 4, 10.5/5 = 2.1 and 8.5/2.1 = 4.047619047619048 which to the nearest tenth is 4.0 or 4......hope this helps,and hope it is correct!!
Answer: A
n-4(32.5) > 300;n > 430tep-by-step explanation:
given that Zack wants to make a profit of more than $300 for painting 4 identical rooms. That is
Profit > $300
Then, the profit he makes is equal to the amount he is paid minus the cost of supplies. The cost of supplies is $32.50 for each room. That is
n - 32.5 and
P + 32.5 × 4
Where 4 = number of rooms
P + 130
The minimum profit = 300 + 130 = $430
Therefore, the inequality and solution that represent the dollar amount, n, that zack must be paid for each room if he is to make a profit of more than 300$ is
n-4(32.5) > 300;n > 430
The angles are supplementary, therefore totaling them at 180°.
And because I'm bored, I'll solve for x for you!
(x + 25) + (9x + 10) = 180
10x + 35 = 180
Subtract 35 from both sides.
10x = 145
Divide by 10 on both sides.
x = 14.5
Answer:
0.9999
Step-by-step explanation:
Let X be the random variable that measures the time that a switch will survive.
If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by
So, the probability that a switch fails in the first year is
Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.
Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and
where
equals combinations of 100 taken k at a time.
The probability that at most 15 fail during the first year is
