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2 years ago

Triangle ABC has vertices of A(–6, 7), B(4, –1), and C(–2, –9). Find the length of the median from angle B in triangle ABC

Mathematics

1 answer:

julsineya [31]2 years ago

7 0

Answer:

Step-by-step explanation:

The median is the segment from vertex B to the midpoint of AC. That midpoint (D) is ...

D = (A + C)/2 = ((-6, 7) +(-2, -9))/2 = (-8, -2)/2

D = (-4, -1)

The length of the midpoint is the length of the segment DB between (-4, -1) and (4, -1). These points both have the same y-coordinate, so the length is the difference of x-coordinates: 4 -(-4) = 8.

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Find dy/dx implicitly and find the largest interval of the form −a < y < a or 0 < y < a such that y is a differentia

mylen [45]

Answer:

dy/dx = -1/√(1 - x²)

For 0 < y < π

Step-by-step explanation:

Given the function cos y = x

-siny dy = dx

-siny dy/dx = 1

dy/dx = -1/siny (equation 1)

But cos²y + sin²y = 1

=> sin²y = 1 - cos²y

=> siny = √(1 - cos²y) (equation 2)

Again, we know that

cosy = x

=> cos²y = x² (equation 3)

Using (equation 3) in (equation 2), we have

siny = √(1 - x²) (equation 4)

Finally, using (equation 4) in (equation 1), we have

dy/dx = -1/√(1 - x²)

The largest interval is when

√(1 - x²) = 0

=> 1 - x² = 0

=> x² = 1

=> x = ±1

So, the interval is

-1 < x < 1

arccos(1) < y < arxcos(-1)

= 0 < y < π

6 0

2 years ago

prove algebraically that the straight line with equation x = 2y + 5 is a tangent to the circle with equation x^2 + y^2 = 5, i ha

Brums [2.3K]

Answer:

I dont even know

Step-by-step explanation:

too complicated

8 0

2 years ago

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La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el

Vika [28.1K]

Answer:

768 libras de fuerza

Step-by-step explanation:

Tenemos que encontrar la ecuación que los relacione.

F = Fuerza necesaria para evitar que el automóvil patine

r = radio de la curva

w = peso del coche

s = velocidad de los coches

En la pregunta se nos dice:

La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.

F ∝ 1 / r

Y luego con el peso del auto

F ∝ w

Y el cuadrado de la velocidad del coche

F ∝ s²

Combinando las tres variaciones juntas,

F ∝ 1 / r ∝ w ∝ s²

k = constante de proporcionalidad, por tanto:

F = k × w × s² / r

F = kws² / r

Paso 1

Encuentra k

En la pregunta, se nos dice:

Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.

F = 400 libras

w = 1600 libras

r = 800

s = 50 mph

Tenga en cuenta que desde el

F = kws² / r

400 = k × 1600 × 50² / 800

400 = k × 5000

k = 400/5000

k = 2/25

Paso 2

¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?

F = ?? libras

w = ya que es el mismo carro = 1600 libras

r = 600

s = 60 mph

F = kws² / r

k = 2/25

F = 2/25 × 1600 × 60² / 600

F = 768 libras

Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.

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2 years ago

Connor borrows $8,000 at a rate of 19% interest per year. What is the amount due at the end of 7 years if the interest is compou

luda_lava [24]

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4 0

1 year ago

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Need help asap. Consider the diagram.

fgiga [73]

ANSWER

<em>alternate interior angles theorem</em>

EXPLANATION

According to the alternate interior angles theorem, when two parallel lines are are intercepted by a straight line (transversal) the angles in the interior corners of a Z-shape pattern are congruent.

From the above diagram line r is parallel to line s, therefore

$\angle \: 3 \cong \angle6$

and

$\angle \: 4\cong \angle5$

because they are alternate interior angles.

See attachment for how to spot alternate interior angles.

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2 years ago

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