Answer:
Neither of the two advertising options meet the goal.
Step-by-step explanation:
Every $4,000 spent on cable TV will reach 160 fans.
Therefore, the goal of reaching 200000 fans will be fulfilled by 
dollars i.e. $5 million which is greater than the budget of $3 million.
Now, every $2,750 spent on radio ads will reach 125 fans.
Therefore, the goal of reaching 200000 fans will be fulfilled by 
dollars i.e. $4.5 million which is again greater than the budget of $3 million.
Therefore, neither of the two advertising options meet the goal. (Answer)
* Craig's answer is not reasonable because to add fractions the denominators must be the same.
** Total distance = 5/8 + 1/2 = 5/8 + 4/8 = 9/8 miles
*** Using the line number to prove the answer:
The line number that represents the problem is in the attached figure.
while the distance between 0 and 1 divided to 8 sections
to represent (5/8) count 5 sections from zero ⇒⇒⇒ point (a)
and to represent (1/2) it is the midpoint between 0 and 1 which mean it is 4 sections but it will be counted from point (a) so, adding 4 sections to point (a) the result will be the point (b)
So, counting from 0 to point (b) will give us 9 sections
and while one section represents (1/8)
So the total distance will be 9 * (1/8) = 9/8 which is agree with the result obtained before
Let x = weight of adult meerkat, y=weight of baby meerkat, Find y.
x=0.776 kg
y+7.47hectogram=x=0.776
Since 1 hectogram = 0.1 kg,
Therefore the weight of baby meerkat is, y= 0.029 kg
Answer:
(A) the specific number of siblings for each randomly selected student
Step-by-step explanation:
First Timothy wants to estimate the mean number of siblings for each student in his school
So he selected a random sample of 75 students, then recorded the number of siblings they have
He later find the mean.
You can see the mean was obtained from the selected group not all students in the school hence option D and E are not correct.
Option A clearly indicates a mean was obtained for the siblings that were from the randomly selected students.
