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Taya2010 [7]
2 years ago
13

The linear equation was solved using these steps. Linear equation: 1 3 (12x + 15) = 7 Step 1: 4x + 5 = 7 Step 2: 4x = 2 Step 3:

x = 1 2 The property that was used in step 1 was the . The property that was used in step 2 was the . The property that was used in step 3 was the .The linear equation was solved using these steps. Linear equation: 1 3 (12x + 15) = 7 Step 1: 4x + 5 = 7 Step 2: 4x = 2 Step 3: x = 1 2 The property that was used in step 1 was the . The property that was used in step 2 was the . The property that was used in step 3 was the .
Mathematics
2 answers:
VikaD [51]2 years ago
8 0

Answer:

Distributive property

Subtraction property

Division property

------------------------------

Tell Doja Cat I said Hi

bagirrra123 [75]2 years ago
5 0

Answer:

The property that was used in step 1 was the distributive property.

The property that was used in step 2 was the subtraction property of equality.

The property that was used in step 3 was the division property of equality.

Step-by-step explanation:

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-67b + 6 ≤ 9b + 43 solve for b
qaws [65]

Answer:

b ≥  -(37/76)

Step-by-step explanation:

5 0
2 years ago
Dan is watching The Birds in his backyard. Of the birds he watches, 9. Of them,or 45%, are sparrows. How many birds are in his b
ra1l [238]

If 9 of the sparrows is 45% of the birds in the backyard, 9/x = 45/100.

Cross multiply to get 9 * 100 = 45x; simplified is 900 = 45x or 20.

This means that there are 20 birds in the backyard. You can check this by dividing 9/20 which equals 45%

5 0
2 years ago
Suppose that the population of deer in a state is 1,500 and is growing 2% each year. Predict the population after 4 years.
DIA [1.3K]
Yes that's right. B 1,624
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2 years ago
The vertices of ΔRST are R(–1,–1), S(–1,11) and T(4,11). Which could be the side lengths of a triangle that is similar but not c
Step2247 [10]
The side lengths could be 10, 24 and 26 units.

We must first find the side lengths.  We use the distance formula to do this.

For RT:
d=\sqrt{(11--1)^2+(-1--1)^2}
\\=\sqrt{(11+1)^2+(-1+1)^2}
\\=\sqrt{12^2+0^2}=\sqrt{144}=12

For ST:
d=\sqrt{(11-11)^2+(4--1)^2}
\\=\sqrt{0^2+(4+1)^2}=\sqrt{5^2}=\sqrt{25}=5

For TR:
d=\sqrt{(11--1)^2+(4--1)^2}
\\=\sqrt{(11+1)^2+(4+1)^2}=\sqrt{12^2+5^2}=\sqrt{144+25}=\sqrt{169}=13

Our side lengths, from least to greatest, are 5, 12 and 13.

To be similar but not congruent, the side lengths must have the same ratio between corresponding sides but not be the same length.  10, 24 and 26 are all 2x the original side lengths, so this works.
5 0
2 years ago
Which statements are true about circle Q? Select three options. The ratio of the measure of central angle PQR to the measure of
kkurt [141]

Answer:

<h3>- The ratio of the measure of central angle PQR to the measure of the entire circle is One-eighth. </h3><h3>- The area of the shaded sector depends on the length of the radius. </h3><h3>- The area of the shaded sector depends on the area of the circle</h3>

Step-by-step explanation:

Given central angle PQR = 45°

Total angle in a circle = 360°

Ratio of the measure of central angle PQR to the measure of the entire circle is \frac{45}{360} = \frac{1}{8}. This shows ratio that <u>the measure of central angle PQR to the measure of the entire circle is one-eighth</u>.

Area of a sector = \frac{\theta}{360}*\pi r^{2}

\theta = central angle (in degree) = 45°

r = radius of the circle = 6

Area of the sector

= \frac{45}{360}*\pi (6)^{2}\\ = \frac{1}{8}*36 \pi\\  = 4.5\pi units^{2}

<u>The ratio of the shaded sector is 4.5πunits² not 4units²</u>

From the formula, it can be seen that the ratio of the central angle to that of the circle is multiplied by area of the circle, this shows <u>that area of the shaded sector depends on the length of the radius and the area of the circle.</u>

Since Area of the circle = πr²

Area of the circle = 36πunits²

The ratio of the area of the shaded sector to the area of the circle = \frac{4.5\pi }{36 \pi } = \frac{1}{8}

For length of an arc

= \frac{45}{360}*2\pi r\\= \frac{45}{360}*2\pi (6)\\= \frac{45}{360}*12 \pi \\= \frac{12\pi }{8} \\= \frac{3\pi }{2} units

ratio of the length of the arc to the area of the circle = \frac{\frac{3\pi}{2} }{36\pi} = \frac{3}{72} =\frac{1}{24}

It is therefore seen that the ratio of the area of the shaded sector to the area of the circle IS NOT equal to the ratio of the length of the arc to the area of the circle

5 0
2 years ago
Read 2 more answers
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