Mr. Richard's science class is conducting a variety of experiments with projectiles and falling objects. Two groups of students
2 answers:
Answer:
1. Group C; 2. Group B; 3. Group D; 4. Group A
Step-by-step explanation:
These equations are in the form
, where v₀ is the initial velocity and h₀ is the initial height.
The first equation has no value for v₀ and a value of 19 for h₀. This means there is no velocity, so the ball is dropped, and since the initial height is 19, it is dropped from 19 meters. This makes it group C.
The second equation has a value of 50 for v₀ and no value for h₀. This means the initial velocity is 50 and there is no initial height. This makes it group B.
The third equation has no value for v₀ and a value of 50 for h₀. This means there is no initial velocity, so the ball is being dropped, and the initial height is 50. This makes it group D.
The fourth equation has a value of 19 for v₀ and no value for h₀. This means the initial velocity is 19 and there is no initial height. This makes it group A.
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Answer:
Step-by-step explanation:
find the attached below
(a) Suppose 
is a solution for this recurrence, with 
. Then
So we expect a general solution of the form
With
, we get four equations in four unknowns:
So the particular solution to the recurrence is
(b) Let
be the generating function for 
. Multiply both sides of the recurrence by 
and sum over all 
.
From here you would write each term as a power series (easy enough, since they're all geometric or derived from a geometric series), combine the series into one, and the solution to the recurrence will be the coefficient of, ideally matching the solution found in part (a).
So we expect a general solution of the form
With
So the particular solution to the recurrence is
(b) Let
From here you would write each term as a power series (easy enough, since they're all geometric or derived from a geometric series), combine the series into one, and the solution to the recurrence will be the coefficient of