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RoseWind [281]
1 year ago
11

Which statements correctly describe the cosine and sine functions? Check all that apply. The cosine function increases on (90°,

180°) and (270°, 360°). The sine function increases on (0°, 90°) and (270°, 360°). The cosine function decreases on (0°, 180°). Both the cosine and sine functions have a minimum value of 0. Both the cosine and sine functions have a maximum value of 1. Both the cosine and sine functions are periodic.
Mathematics
1 answer:
Jet001 [13]1 year ago
4 0

Answer:

The three correct answers are B "The sine function increases on (0°, 90°) and (270°, 360°)." , E "Both the cosine and sine functions have a maximum value of 1.", and F "Both the cosine and sine functions are periodic."

Step-by-step explanation:

Hope this helps <3

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A coordinate plane showing Running. The x-axis shows seconds, the y-axis shows feet. One solid line showing Moises starting at (
torisob [31]

Answer:

Step-by-step explanation:

s

7 0
1 year ago
the total reimbursement (in dollars) for driving a company car m miles can be modeled by the function f(x) = 0.45m +5. After a p
Luba_88 [7]

Answer:

The slope becomes 0.5625 and y intercept becomes 12.5.

$65.9375

Step-by-step explanation:

Given that

the total reimbursement function in terms of m miles:

f(x) = 0.45m +5

After the policy change, 5 more dollars are added and then total amount is multiplied by 1.25.

To find:

How to transform the graph of f.

Total reimbursement for a trip of 95 miles?

Solution:

f(x) = 0.45m +5 can also be written as:

y = 0.45m +5

It is nothing but slope intercept form, comparing with Y = M X+ C

M is the slope and C is the y intercept.

Slope of the graph is 0.45.

Y intercept is 5.

After change in the function, first of all add $5.

0.45m +  5+5 = 0.45m+10

Now, multiply with 1.25

Resulting function becomes:

f(x) =1.25\times (0.45m+10)\\\Rightarrow f(x) =0.5625m+12.5

Kindly refer to the attached image for the graph of the two functions.

Now, the slope becomes 0.5625 and y intercept becomes 12.5. This is the transformation.

To find the reimbursement for a trip of 95 miles:

Put m = 95

f(95) =0.5625\times 95+12.5 = \bold{\$65.9375 }

8 0
2 years ago
Evaluate the integral. 17 sin2(x) cos3(x) dx step 1 since 17 sin2(x) cos3(x) dx has an odd power of of cos(x), we will convert a
lord [1]
To evaluate 17 int (sin^2 (x)  cos^3(x))
From Trig identity. Cos^2(x) + sin^2(x) =1. Cos^2(x) = 1 - sin^2 (x) 
Cos^3(x) = cosx * (1 - sin^2 (x)) = cosx - cosxsin^2x
So we have 17 int (sin^2x(cosx - cosxsin^2x))
int (sin^2x(cosx)dx - int (sin^4xcosx)dx. ----------(1)
Let u = sinx then du = cosxdx
Substituting into (1) we have
int (u^2du) - int (u^4du)
u^3/3 - u^5/5
Substitute value for u we have 
(sinx)^3/3 - (sinx)^5/5
Hence we have 17 [ sin^3x/3 - sin^5x/5]
7 0
1 year ago
`bar(JK)` is dilated by a scale factor of n with the origin as the center of dilation, resulting in the image `bar(J'K')`. The s
dalvyx [7]

Answer:

Length of Bar JK=l

Bar (JK) is dilated by a scale factor of n, having origin as the center of dilation.

New line segment formed named  bar (J'K').

As given slope of bar(JK) =m

When we dilate a line segment with respect to origin , having origin as the center of dilation, there is no effect of slope on Dilation.

Length of bar (J'K')= (Length of bar JK)×(Scale factor)

                             = l×n Or n×l

Option (D) is correct.

                           




7 0
2 years ago
Read 2 more answers
An in-ground pond has the shape of a rectangular prism. The pond has a depth of 24 inches and a volume of 72,000 cubic inches. T
Ksenya-84 [330]
Let
x-------> <span>the length of the pond
</span>y-------> the  width of the pond

we know that
[volume of the pond]=area of the base*deep
area of the base=volume/deep
volume=72000 in³
deep=24 in
area of the base=72000/24------> 3000 in²

area of the base=x*y
3000=x*y-------> equation 1
x=2y-----> equation 2

substitute equation 2 in equation 1
3000=[2y]*y------> 2y²=3000-----> y²=1500------> y=38.7 in
x=2y----> x=2*38.7----> x=77.4 in

the answer is
the length of the pond is 77.4 in
the  width of the pond is 38.7 in

5 0
1 year ago
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