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1 year ago

Solve the system of equations. -9Y +4X -20 =0 -7Y +16 X -80 =0 X= Y=

Mathematics

1 answer:

Fofino [41]1 year ago

3 0

Answer:

X=5, Y=0

Step-by-step explanation:

-9Y +4X -20=0

-7Y+16X-80=0

1. We can multiply the first equation by 4. This will equal to -36Y +16X-80=0.

-36Y +16X -80 =0

-7Y+16X-80=0

2. We can subtract these two equations.

-36Y +16X -80 =0

-7Y+16X-80=0

We will get -29Y =0. Y=0.

3. Then we can substitute y into the first equation. -9(0) +4x-20 =0. 4x=20. x=5

X=5, Y=0

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2 years ago

Find the quotient of 2,300 and (0.4 · 10^-8). In your final answer, include all of your calculations.

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Answer:

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quotient of 2,300 and (0.4x10^-8) is

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1 year ago

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1 year ago

An antique store increases all of its prices by $40\%$, and then announces a $25\%$-off-everything sale. What percent of the ori

Nostrana [21]

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2 years ago

Read 2 more answers

The price of a train ticket consists of an initial fee plus a constant fee per stop.

murzikaleks [220]

Answer:

Initial Fee is $2.

Step-by-step explanation:

Given:

Stops Price (dollars)

3 6.50

7 12.50

11 18.50

Also Given:

The price of a train ticket consists of an initial fee plus a constant fee per stop.

So let the Cost of initial fee be 'x'.

Also Let the Cost of Constant fee be 'y'.

Now Equation can framed as;

$Price (P) = x + (y\times \textrm{Number of Stops})$

Now According to table;

Number of stops = 3

Price = 6.50

So equation can be framed as;

$x+3y =6.50 \ \ \ \ equation \ 1$

Also According to table;

Number of stops = 7

Price = 12.50

So equation can be framed as;

$x+7y =12.50 \ \ \ \ equation \ 2$

Now Subtracting equation 1 from equation 2 we get;

$(x+7y)-(x+3y) =12.50-6.50\\\\x+7y-x-3y=6\\\\4y =6\\\\y= \frac{6}{4}=\$1.5$

Substituting the value of y in equation 1 we get;

$x+3\times1.5=6.50\\\\x+4.5=6.50\\\\x =6.50-4.5 = \$2$

Hence Initial Fee is $2.

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2 years ago

Read 2 more answers