Question

The price of a train ticket consists of an initial fee plus a constant fee per stop.

Answer 1

Answer:

Initial Fee is $2.

Step-by-step explanation:

Given:

Stops  Price (dollars)

3         6.50

7         12.50

11         18.50

Also Given:

The price of a train ticket consists of an initial fee plus a constant fee per stop.

So let the Cost of initial fee be 'x'.

Also Let the Cost of Constant fee be 'y'.

Now Equation can framed as;

$Price (P) = x + (y\times \textrm{Number of Stops})$

Now According to table;

Number of stops = 3

Price = 6.50

So equation can be framed as;

$x+3y =6.50 \ \ \ \ equation \ 1$

Also According to table;

Number of stops = 7

Price = 12.50

So equation can be framed as;

$x+7y =12.50 \ \ \ \ equation \ 2$

Now Subtracting equation 1 from equation 2 we get;

$(x+7y)-(x+3y) =12.50-6.50\\\\x+7y-x-3y=6\\\\4y =6\\\\y= \frac{6}{4}=\ 1.5$

Substituting the value of y in equation 1 we get;

$x+3\times1.5=6.50\\\\x+4.5=6.50\\\\x =6.50-4.5 = \ 2$

Hence Initial Fee is $2.

Answer 2

Answer:

$2.00

Step-by-step explanation: