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emmasim [6.3K]
2 years ago
13

A 100-square grid has 70 shaded squares. Explain how you could express this model as a fraction, percent, and decimal.

Mathematics
2 answers:
slava [35]2 years ago
6 0
The fraction of squares shaded to total squares is 70/100  or 7/10
With a percent, 70% of all of the squares are shaded
With a decimal, there are 0.7 shaded blocks for every total block, so it is 0.7
Hope this helps!
uranmaximum [27]2 years ago
4 0

Answer:

sample answer : 70 out of 100 is the ratio  , so it represents 70%.  can be reduced by dividing the numerator and the denominator by 10 to get the reduced fraction . Dividing 7 by 10 results in the decimal equivalent 0.70

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Answer:

  1. 7 is (14x)°

Step-by-step explanation:

In the diagram, the measure of angle 2 is 126°, the measure of angle 4 is (7x)°, and the measure of angle 5 is (4x + 4)°. A transversal intersects 2 lines to form 8 angles. Clockwise from the top left, the angles are 1, 2, 3, 4; 5, 6, 7, 8. What is the measure of angle 7, to the nearest degree? The nearest degree measure of angle 7 is (14x)°

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1. Walking to improve health. In a study investigating a link between walking and improved health (Social Science & Medicine
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Answer:

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Null hypothesis:\mu \geq 5.5  

Alternative hypothesis:\mu < 5.5  

b) For this case since we want to determine if the true mean is lower than an specified value is a one tailed test

c) For this case the significance level is given \alpha=0.01 and we want to find the critical value, so we need to find a critical value on the normal standard distribution who accumulate 0.01 of the area on the right tail and if we use excel or a table we got:

z_{cric}= -2.326

And the rejection zone would be: (\infty ,-2.326)

And the region is on the figure attached

Step-by-step explanation:

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true average number of days in the past month that adults walked for the purpose of health or recreation is lower than 5.5 days (a;ternative hypothesis) , the system of hypothesis would be:  

Null hypothesis:\mu \geq 5.5  

Alternative hypothesis:\mu < 5.5  

Part b

For this case since we want to determine if the true mean is lower than an specified value is a one tailed test

Part c

For this case the significance level is given \alpha=0.01and we want to find the critical value, so we need to find a critical value on the normal standard distribution who accumulate 0.01 of the area on the right tail and if we use excel or a table we got:

z_{cric}= -2.326

And the rejection zone would be: (\infty ,-2.326)

And the region is on the figure attached

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hope this helps

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Answer:

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