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iren [92.7K]
2 years ago
16

Kevin says that lines p and m will eventually intersect. Lines A and B intersect. Plane A contains lines p, m, and n. Line n is

horizontal on the plane. Lines p and m are both going in the same direction and are identical. Plane B contains vertical line l which forms a right angle with line n. Is Kevin correct?
Mathematics
1 answer:
ANTONII [103]2 years ago
8 0

Answer:

No, because they are parallel.

Step-by-step explanation:

The lines p and m will not intersect, so Kevin is not correct.

It is given that planes A and B intersects. The plane A contains the line p, m and n on its plane. The lines p and m are parallel to each other. They are identical and move in the same direction.

Since the line p and m are parallel, they will not meet each other at any point because parallel lines does not intersect or meet at a point, they run parallelly along each other.

So, line p and m will not intersect.

Thus the answer is " No, because they are parallel."

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Suppose a rectangular pasture is to be constructed using 1 2 linear mile of fencing. The pasture will have one divider parallel
timama [110]

Answer:

\displaystyle A=\frac{1}{192}

Step-by-step explanation:

<u>Maximization With Derivatives</u>

Given a function of one variable A(x), we can find the maximum or minimum value of A by using the derivatives criterion. If A'(x)=0, then A has a probable maximum or minimum value.

We need to find a function for the area of the pasture. Let's assume the dimensions of the pasture are x and y, and one divider goes parallel to the sides named y, and two dividers go parallel to x.

The two divisions parallel to x have lengths y, thus the fencing will take 4x. The three dividers parallel to y have lengths x, thus the fencing will take 3y.

The amount of fence needed to enclose the external and the internal divisions is

P=4x+3y

We know the total fencing is 1/2 miles long, thus

\displaystyle 4x+3y=\frac{1}{2}

Solving for x

\displaystyle x=\frac{\frac{1}{2}-3y}{4}

The total area of the pasture is

A=x.y

Substituting x

\displaystyle A=\frac{\frac{1}{2}-3y}{4}.y

\displaystyle A=\frac{\frac{1}{2}y-3y^2}{4}

Differentiating with respect to y

\displaystyle A'=\frac{\frac{1}{2}-6y}{4}

Equate to 0

\displaystyle \frac{\frac{1}{2}-6y}{4}=0

Solving for y

\displaystyle y=\frac{1}{12}

And also

\displaystyle x=\frac{\frac{1}{2}-3\cdot \frac{1}{12}}{4}=\frac{1}{16}

Compute the second derivative

\displaystyle A''=-\frac{3}{2}.

Since it's always negative, the point is a maximum

Thus, the maximum area is

\displaystyle A=\frac{1}{12}\cdot \frac{1}{16}=\frac{1}{192}

6 0
2 years ago
A farmer wants to net at least $10,000/acre on the sale of his 80-acre property. If he allows for a total of 10% for commissions
lara [203]

Answer:

$11,111.11

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Percentage of commission and closing cost incurred by him = 10%

out of 100 %, he will incur cost of 10%,

rest of them will be with him.

In percentage money he would have be = (100 - 10)% = 90%

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Let the list price be $x

Given that 90% of this $x will be with farmer which is equal to

90% of x = 90/100 * x = 0.9 x

It is given that he wants to net $10000

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Listing price per acre should be at least  $11,111.11.

5 0
2 years ago
Marcia has two credit cards and would like to consolidate the two balances into one balance on the card with the lower interest
swat32
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2 years ago
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