Answer:
20 and 16
Step-by-step explanation:
Let us find x and y.
x – y = 4 _____(1)
x/2 + y/2= 18___(2)
Multiply (2) by 2 and add to (1)
x - y = 4
+<u>(x + y = 36)</u>
<u>2x = 40</u>
=> x = 40 / 2 = 20
From (1):
20 - y = 4
=> y = 20 - 4 = 16
The two numbers are 20 and 16.
I think they all apply (tick all the statements) since a rigid transformation doesn’t affect the shape of the triangle simply it’s position.
Answer:
Step-by-step explanation:
The mentioned relationship for the weight, in pounds, of the kitten with respect to time, in weeks, is

Weight of the kitten after 10 weeks

pounds
This modeled equation is based on the observation of the early age of a kitten where the kitten is in its growth period, but in the early stage the growth rate in the weight of the kitten was the same but the growth of any living beings continues till the adult stage. So, after some time, in real life situation, this weekly change in weight will become zero, So, this model is not suitable to measure the weight of the kitten over the larger time period.
Here, t= 10 weeks is nearby the observed time period, so the linearly modeled equation can be used to predict the weight.
Hence, the weight of the kitten after 10 weeks is 16.5 pounds.
The function given is a quadratic function, so the graph will be a parabola. It'll look similar to the photo attached. The minimum cost will be at the vertex of the parabola because that is its lowest point! To find the x-value of the vertex (which is what the question is looking for), use the vertex formula: x = -b/2a. The variable b is the coefficient of the x term in the function, and the variable a is the coefficient of the x² term. In this case, a = 0.125 and b = -5.
x = -(-5)/2(0.125)
x = 5/0.25
x = 20
So, 20 gas grills should be produced each day to maintain minimum costs. Hope that helps! :)
Answer
given,
thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.
X = U[0.95,1.05] 0.95≤ x ≤ 1.05
the cumulative distribution function of flange
F(x) = P{X≤ x}=
=
b) P(X>1.02)= 1 - P(X≤1.02)
= 
= 0.3
c) The thickness greater than 0.96 exceeded by 90% of the flanges.
d) mean = 
= 1
variance = 
= 0.000833