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lina2011 [118]
2 years ago
7

A machine produces 374 bolts in 33 minutes. At the same rate, how many minutes would it take to produce 272 bolts?

Mathematics
2 answers:
ikadub [295]2 years ago
8 0
The answer is 24 minutes
lesya [120]2 years ago
4 0
374 = 33
272 = x

374/33 = 272/x

x=(33*272)/374=24 minutes
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Nevaeh has $560 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax. She buys
AnnyKZ [126]

Answer:

The number of outfits she purchase with the left money = 3

Step-by-step explanation:

The exact question is as follows :

Given - Nevaeh has $560 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax. She buys a new bicycle for $383.32. She buys 4 bicycle reflectors for $9.09 each and a pair of bike gloves for $21.07. She plans to spend some or all of the money she has left to buy new biking outfits for $39.75 each.

To find - Write and solve an inequality which can be used to determine  x  where x, the number of outfits Nevaeh can purchase while staying within her budget.

Proof -

Given that,

Total money Nevaeh have = $ 560

She spent money on bicycle = $ 383.32

She spend money on 1 reflector = $ 9.09

As she buy 4 bicycle reflector, So

Total money spent on bicycle reflector = $ 4×9.09 = $ 36.36

She spend money on a pair of bike gloves = $ 21.07

So,

Total money she spend on the items = $ 383.32 + 36.36 + 21.07

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⇒Total money she spend on the items = $ 440.75

So,

Total money Left = $ 560 - $ 440.75 = $ 119.25

Now,

She plans to spend some or all of the money she has left to buy new biking outfits for $ 39.75 each.

Let us assume ,

The number of outfits she purchase with the left money = x

AS,

each outfit cost = $ 39.75

So, x outfits cost = $ 39.75 x

Now,

$ 39.75 x = $ 119.25     (because total money left = $ 119.25)

⇒ x = \frac{119.25}{39.75} = 3

∴ we get

The number of outfits she purchase with the left money = x = 3

6 0
1 year ago
The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act
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Step-by-step explanation:

Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the actual temperature of the medium, and standard deviation σ.

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The critical z-value for 95% confidence : z_{\alpha/2}=1.960 (1)

Since , z=\dfrac{x-\mu}{\sigma} (where x be any random variable that represents the temperature reading from a thermocouple.)

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\dfrac{x-\mu}{\sigma}=1.96\\\\ x-\mu=1.96\sigma     (2)

Also,  all readings are within 0.5° of μ,

i.e. x-\mu

i.e. 1.96\sigma   [From (2)]

i.e. \sigma  

i.e. \sigma\approx0.2551

The required standard deviation : \sigma=0.2551

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2x+15y=2,960 would be the equation
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All u need to do is subtract the bigger number from the smaller one
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